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The required probability is 
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that, 
Probability for first draw to be non-defective 
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective 
(printers after first slot = 10; total defective printers = 2)
Then, total probability 
Answer:
24/4
Step-by-step explanation:
all you have to do is multiply 4x6=24
<span>1. take English and niether of the other two?
</span>36-6 that we know take all 3
This leave 30.
Subtract the 6 from those taking history and English. Leaves 10.
Subtract the 10 from those taking English.
This leaves 20.
Subtract the 6 from those taking political science and English. Leaves 8.
Subtract 8 from those taking English.
Leaves 12
<span>
2. take none of the three courses? </span>
<span>
3. take history, but niether of the other two
</span>Do the same with history as we did with English.
32-6 = 26 -10=16-10=6
<span>
4. take political science and history but not english
</span>16-6 (that take all 3) = 10
Hope at least the partial answer helps!
Answer:
50/50
Step-by-step explanation:
they both have 2 sides. half of that is %50
