Answer:
Length equals 16 and Width equals 4
Step-by-step explanation:
First let us create an equation. We can use L and W for length and width.
If the length is 4 times the width, then we end up with: L = 4W
It then says, " If its length were diminished by 6 meters and its width were increased by 6 meters, it would be a square."
Since a square has an equal length and width then we end up with:
L - 6 = W + 6
Knowing this we can just substitute the first equation into the second one leaving us with: 4W - 6 = W + 6
We then remove a W from both sides so that the right side is left with a 6, and add 6 to both sides to remove the -6 from the left one.
This leaves us with 3W = 12
W = 4, and if we put that into our first equation, L = 4W, then Length equals 16, and Width equals 4. We can check this by putting it into the 2nd equation. 16 - 6 = 4 + 6.
If these triangles are congruent, then side RS is congruent to side TV and that means that y = 4 - x. If y = 4-x, we can sub that into the next equation where side RV = side ST and 1 = 4x - y. If y = 4-x, we sub in accordingly to get 1 =4x - (4 - x). That simplifies to 1 = 4x - 4 + x which is, combining like terms, 5 = 5x. That means that x = 1. If x = 1, and y = 4 - x, then y = 4 - 1 and y = 3. There you go!
You find a point at the intersection of a plane and line.
The answer is C (289pi/6 mi2)
It is between the first two I believe it is the first one I am not absolutly sure though
