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LuckyWell [14K]
4 years ago
14

872,000,000,000 in standard form

Mathematics
2 answers:
rewona [7]4 years ago
8 0
The answer would be 8.72^11
BabaBlast [244]4 years ago
5 0

Answer:

eight hundred and seventy-two trillion

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Helpp me please!!!!!!
Alexeev081 [22]

Answer:

a. Inscribed angle = <WXY

b. Minor arc = arc(XY)

c. VWX

d. m(VWX) = 180°

e. m<VUW = 110°

Step-by-step explanation:

a. The angle, <WXY has its vertex on the circumference of the circle. Therefore, it can be referred to as an inscribed angle of the circle with center U.

Inscribed angle = <WXY

b. Arc(XY) is a minor arc because it is smaller than half of circle with center U.

Minor arc = arc(XY)

c. A semicircle is half of a full rotation for a circle. From the diagram, a semicircle is VWX

d. m(VWX) = Half the rotation of a full circle = 180°

e. m<VUW = arc(VW) (measure of central angle = measure of arc)

m<VUW = 110° (Substitution)

3 0
3 years ago
What is 87 over 62 in simplest form?
lawyer [7]
87/62 = 1 and 25/62 (simplest form)
4 0
3 years ago
If a train travels one mile (5,280 feet) while climbing a hill at an angle of five degrees, approximately how many vertical feet
Paul [167]

to calculate the vertical height multiply the hypotenuse ( 5280) by the sin of the angle (5)

5280 x sin(5) = 460.1823

round off to 460 feet

6 0
4 years ago
Use the denition of the derivative to find f 0 (3), where f (x) = 3x+5 / 2x−1
Crazy boy [7]

Answer:

f'(3)= -\frac{13}{25}

Step-by-step explanation:

We are asked to find f'(3) of function f(x)=\frac{3x+5}{2x-1} using definition of derivatives.

Limit definition of derivatives:

f'(x)= \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}

Let us find f(3+h) and f(3).

f(3+h)=\frac{3(3+h)+5}{2(3+h)-1}

f(3+h)=\frac{9+3h+5}{6+2h-1}\\\\f(3+h)=\frac{3h+14}{2h+5}

f(3)=\frac{3(3)+5}{2(3)-1}

f(3)=\frac{9+5}{6-1}\\\\f(3)=\frac{14}{5}

Substituting these values in limit definition of derivatives, we will get:

f'(3)= \lim_{h \to 0} \frac{f(3+h)-f(3)}{h}

f'(3)= \lim_{h \to 0} \frac{\frac{3h+14}{2h+5}-\frac{14}{5}}{h}

Make a common denominator:

f'(3)= \lim_{h \to 0} \frac{\frac{(3h+14)*5}{(2h+5)*5}-\frac{14(2h+5)}{5(2h+5)}}{h}

f'(3)= \lim_{h \to 0} \frac{\frac{5(3h+14)-14(2h+5)}{5(2h+5)}}{h}

f'(3)= \lim_{h \to 0} \frac{5(3h+14)-14(2h+5)}{5h(2h+5)}

f'(3)= \lim_{h \to 0} \frac{15h+70-28h-70}{5h(2h+5)}

f'(3)= \lim_{h \to 0} \frac{-13h}{5h(2h+5)}

Cancel out h:

f'(3)= \lim_{h \to 0} \frac{-13}{5(2h+5)}

f'(3)= \frac{-13}{5(2(0)+5)}

f'(3)= \frac{-13}{5(5)}

f'(3)= -\frac{13}{25}

Therefore, f'(3)= -\frac{13}{25}.

8 0
3 years ago
How many minutes are there in a quarter of a day?
svlad2 [7]
There are 360 minutes.
7 0
3 years ago
Read 2 more answers
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