Yes, a rhombus is a rectangle if it has a similar shape of a square.Hope that helped
Interpreting the inequality, it is found that the correct option is given by F.
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- The first equation is of the line.
- The equal sign is present in the inequality, which means that the line is not dashed, which removes option G.
In standard form, the equation of the line is:



Thus it is a decreasing line, which removes options J.
- We are interested in the region on the plane below the line, that is, less than the line, which removes option H.
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- As for the second equation, the normalized equation is:



- Thus, a circle centered at the origin and with radius 2.
- Now, we have to check if the line
, with coefficients
, intersects the circle, of centre 
- First, we find the following distance:

- Considering the coefficients of the line and the center of the circle.

- This distance is less than the radius, thus, the line intersects the circle, which removes option K, and states that the correct option is given by F.
A similar problem is given at brainly.com/question/16505684
Find the critical points of f(y):Compute the critical points of -5 y^2
To find all critical points, first compute f'(y):( d)/( dy)(-5 y^2) = -10 y:f'(y) = -10 y
Solving -10 y = 0 yields y = 0:y = 0
f'(y) exists everywhere:-10 y exists everywhere
The only critical point of -5 y^2 is at y = 0:y = 0
The domain of -5 y^2 is R:The endpoints of R are y = -∞ and ∞
Evaluate -5 y^2 at y = -∞, 0 and ∞:The open endpoints of the domain are marked in grayy | f(y)-∞ | -∞0 | 0∞ | -∞
The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:The open endpoints of the domain are marked in grayy | f(y) | extrema type-∞ | -∞ | global min0 | 0 | global max∞ | -∞ | global min
Remove the points y = -∞ and ∞ from the tableThese cannot be global extrema, as the value of f(y) here is never achieved:y | f(y) | extrema type0 | 0 | global max
f(y) = -5 y^2 has one global maximum:Answer: f(y) has a global maximum at y = 0
Answer:
Andre scored 14 points.
Equation: x = 14
Step-by-step explanation:
Let the number of points Andre scored be x.
Diego's points = x-9
Noah's points = (x-9) × 2
= 2x-18
Now, you know the exact value of Noah's points which is 10.
2x-18 = 10
Isolate the 2x.
2x = 10+18
= 28
x = 28÷2
= 14
Answer:
I would say 49 is your answer
Step-by-step explanation:
53 plus 78 qould equal 131
subtract 131 from 180 and you get 49
add up all your numbers including x then they should all equal 180