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Rina8888 [55]
4 years ago
10

For the month of October Lisa plan to go running every fifth day and walk every sixth day. If she begins on October 1, on what d

ay of the month will she run and walk during the same day?
Mathematics
1 answer:
Tomtit [17]4 years ago
4 0

Answer:

October 30 is the day of the month she will run and walk during the same day.

Step-by-step explanation:

To determine what day of the month will she run and walk during the same day, we will list the days she plans to go running and the days she plans to walk.

From the question,  Lisa plan to go running every fifth day and walk every sixth day, then

If she begins on October 1, the days she will run will be

October 5, October 10, October 15, October 20, October 25, and October 30;

while the days she will walk will be

October 6, October 12, October 18, October 24, and October 30.

Since October 30 occurred among the days she will run and walk, then October 30 is the day of the month she will run and walk during the same day.

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the lengths of three pieces of wire are in the ratio 10:15:8. if the length of the shortest piece of wire is 2.4 m, find the dif
luda_lava [24]
Hope this helps you.

3 0
3 years ago
Ruben bought 6 new books for his collection. This increased his collection by 12%. How many books did he have before his purchas
Norma-Jean [14]

Answer:  The required number of books that Ruben had before purchases is 50.

Step-by-step explanation:  Given that Ruben bought 6 new books for his collection that increased his collection by 12%.

We are to find the number of books that Ruben had before purchases.

Let x denotes the number of books that Ruben had before purchases.

Then, according to the given information, we have

x+6=x+12\%\times x\\\\\\\Rightarrow 6=\dfrac{12}{100}x\\\\\\\Rightarrow 6=\dfrac{3x}{25}\\\\\\\Rightarrow 3x=150\\\\\Rightarrow x=\dfrac{150}{3}\\\\\Rightarrow x=50.

Thus, the required number of books that Ruben had before purchases is 50.

4 0
3 years ago
Write a phrase for each expression: <br> 10y<br><br> x - 3<br><br> 12n
kati45 [8]
10 times a number y
3 subtracted from a number x
12 times a number n

hope this helped :)
6 0
3 years ago
Read 2 more answers
5/7 is a fraction in simplest form.<br><br> Group of answer choices<br><br> True<br><br> False
katen-ka-za [31]

Answer:

True

Step-by-step explanation:

If an equation is in simplest form, that means either a number is prime or neither number shares a common factor. 5 and 7 are prime numbers which means they have no common factor. For example 6/12 is not simplest form because they share a common factor (2 and 3).

6 0
3 years ago
A new post-surgical treatment is being compared with a standard treatment. Seven subjects receive the new treatment, while seven
a_sh-v [17]

Answer:

(17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745

(17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255

Step-by-step explanation:

For this case we have the following info given:

Treatment: 12 13 15 19 20 21 24

Control: 18 23 24 30 32 35 39

We can find the sample mean and deviations with the the following formulas:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}

And repaplacing we got:

\bar X_T = 17.714 the sample mean for treatment

\bar X_C = 28.714 the sample mean for treatment

s_T= 4.461 the sample deviation for treatment

s_C= 7.387 the sample deviation for control

n_T= n_C= 7 the sample size for each sample

The degrees of freedom are given by:

df= 7+7-2= 12

The confidence interval for the difference of means is given by:

(\bar X_T -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_T}{n_T} +\frac{s^2_C}{n_C}}

The confidence is 98% so then the significance is \alpha=0.02 and \alpha/2 =0.01. Then the critical value would be:

t_{\alpha/2}=2.681

And replacing we got:

(17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745

(17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255

4 0
3 years ago
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