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Rina8888 [55]
3 years ago
10

For the month of October Lisa plan to go running every fifth day and walk every sixth day. If she begins on October 1, on what d

ay of the month will she run and walk during the same day?
Mathematics
1 answer:
Tomtit [17]3 years ago
4 0

Answer:

October 30 is the day of the month she will run and walk during the same day.

Step-by-step explanation:

To determine what day of the month will she run and walk during the same day, we will list the days she plans to go running and the days she plans to walk.

From the question,  Lisa plan to go running every fifth day and walk every sixth day, then

If she begins on October 1, the days she will run will be

October 5, October 10, October 15, October 20, October 25, and October 30;

while the days she will walk will be

October 6, October 12, October 18, October 24, and October 30.

Since October 30 occurred among the days she will run and walk, then October 30 is the day of the month she will run and walk during the same day.

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Which of the following describes the correct process for solving the equation 2x − 4 = 20 and arrives at the correct solution?
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Answer:

a) Add 4 to both sides, and then divide by 2. The solution is x=12.

Step-by-step explanation:

Question:

Which of the following describes the correct process for solving the equation 2x − 4 = 20 and arrives at the correct solution?

a) Add 4 to both sides, and then divide by 2. The solution is x = 12.

b) Divide both sides by −4, and then subtract 2. The solution is x = −7.

c) Subtract 4 from both sides, and then divide by 2. The solution is x = −12.

d) Multiply both sides by −4, and then divide by 2. The solution is x = −40.

Solution:

Given equation:

2x-4=20

We need to determine the steps in order to solve for x.

Solving for x.

Step 1: Adding 4 both sides.

2x-4+4=20+4

2x=24

Step 2: Dividing both sides by 2.

\frac{2x}{2}=\frac{24}{2}

∴ x=12

Thus, we added 4 both sides and then divided both sides by 2 to get solution = 12

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