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Rina8888 [55]
3 years ago
10

For the month of October Lisa plan to go running every fifth day and walk every sixth day. If she begins on October 1, on what d

ay of the month will she run and walk during the same day?
Mathematics
1 answer:
Tomtit [17]3 years ago
4 0

Answer:

October 30 is the day of the month she will run and walk during the same day.

Step-by-step explanation:

To determine what day of the month will she run and walk during the same day, we will list the days she plans to go running and the days she plans to walk.

From the question,  Lisa plan to go running every fifth day and walk every sixth day, then

If she begins on October 1, the days she will run will be

October 5, October 10, October 15, October 20, October 25, and October 30;

while the days she will walk will be

October 6, October 12, October 18, October 24, and October 30.

Since October 30 occurred among the days she will run and walk, then October 30 is the day of the month she will run and walk during the same day.

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Find the median and mode(s)of the data set 53,53.5,57,54,54.5,47,55,54.5​
ella [17]

Answer:

the median is the middle number.

and the mode is the number that occurs most.

so if we put everything in order

53, 53.5, 54, 54.5, 54.5, 55, 57

so the mode would be 54.5 cause it occurs twice

and the median would be somewhere in between 54 and 54.5

4 0
4 years ago
Read 2 more answers
7. A crate of soft drinks contains 9 bottles of coke, 6 bottles of pepsi and 4 bottles of limca. Ademola picks one bottle of sof
Mekhanik [1.2K]

The probability that the events (a) they both picked Limca = 0.04, (b) Ademola only picked Pepsi = 0.32, (c) They both picked the same brand = 0.33 (d) They picked different brand=0.67.

<h3>What is probability?</h3>

Probability is the fraction of the required outcome event divided by the number of possible outcomes of events.

Total possible outcome of the event of picking drinks contained in the crate = 19

Hence, we can compute the following as follows;

(a) The probability they both picked Limca = (4/19)×(3/18)

Limca = 12/342

Limca = 0.04

(b) The probability Ademola only picked pepsi = 6/19

pepsi = 0.32

(c) The probability they both picked the same brand = (9/19)×(8/18)+(6/19)×(5/18)+(4/19)×(3/18)

=(72+29+12)/342

= 114/342

= 0.33

(d) The probability they picked different brand = (9/19)×(6/18)+(9/19)×(4/18)+(6/19)×(9/18)+(6/19)×(4/18)+(4/19)×(9/18)+(4/19)×(6/18)

The probability they picked different brand = (54+36+54+24+36+24)/342

The probability they picked different brand = 228/332

The probability they picked different brand = 0.67

Therefore, the probability for events (a) is 0.04, (b) is 0.32, (c) is 0.33 and (d) is 0.67.

Know more about probability here: brainly.com/question/24830485

#SPJ1

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1 year ago
Algebra 2 Please Help
hammer [34]
No sé lo que quieres decir
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3 years ago
Unit 3 | Lesson 9
Charra [1.4K]
The formula d = rt gives the distance traveled in time t at rate r. A bicyclist rides for 1.5 hours and travels 25 miles. 
d= D. 37.5 miles per hour
r= 25
t=1.5
25*1.5
=37.5

D.
37.5 miles per hour
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3 years ago
Use the box plot to explain what you know about the spread of this data set.
k0ka [10]

Answer:

The Middle is 50, The outliers are 20 and 75

Step-by-step explanation:

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3 years ago
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