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Feliz [49]
3 years ago
5

Find the median and mode(s)of the data set 53,53.5,57,54,54.5,47,55,54.5​

Mathematics
2 answers:
nydimaria [60]3 years ago
6 0
Both mode and median is 54.5

You have to put them in order...

The number in the middle off all the numbers is the median so if you go back n forth crossing off the numbers your left with 54.5

The mode is the number you see the most sooo 54.5
ella [17]3 years ago
4 0

Answer:

the median is the middle number.

and the mode is the number that occurs most.

so if we put everything in order

53, 53.5, 54, 54.5, 54.5, 55, 57

so the mode would be 54.5 cause it occurs twice

and the median would be somewhere in between 54 and 54.5

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Ivan has 6 times as many blue beads as red beads. he has 49 red and blue beads in all. how many blue beads does Ivan have
salantis [7]

Let

x--------> the number of blue beads

y--------> the number of red beads

we know that

x+y=49

x=49-y -------> equation 1

x=6y ------> equation 2

equate equation 1 and equation 2

49-y=6y\\ 6y+y=49\\ 7y=49\\\\ y=\frac{49}{7} \\  \\ y=7

find the value of x

x=6*7\\ x=42

therefore

the answer is

Ivan has 42 blue beads

3 0
3 years ago
Read 2 more answers
What is x in this equation −4.5= −0.5(x − 7.1)
Umnica [9.8K]

Answer:

x=16.1

Step-by-step explanation:

-4.5= -0.5(x -7.1)

Divide both sides by -0.5

9=x-7.1

Add 7.1 to both sides

16.1=x

Hope this helps!

7 0
3 years ago
A is (4,15) and b is (8,1) what is the midpoint of AB?
antoniya [11.8K]

Answer:

(6,8)

Step-by-step explanation:

midpoint=(x1+x2)÷2,(y1+y2)÷2

a(4,15) b(8,1)

x=4+8=12÷2=6

y=15+1=16÷2=8

Answer=(6,8)

8 0
3 years ago
Answer this please 20 points
8090 [49]

Do you know What topic this is ?


7 0
3 years ago
Look at the rectangle and the square:
OlgaM077 [116]

Answer:

Sam is incorrect

Step-by-step explanation:

We can calculate the lengths of the diagonals using Pythagoras' identity.

The diagonals divide the rectangle and square into 2 right triangles.

Consider Δ SRQ from the rectangle

SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )

SQ = \sqrt{180} ≈ 13.4 in ( to 1 dec. place )

Consider Δ ONM from the square

OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )

OM = \sqrt{72} ≈ 8.5 in ( to 1 dec. place )

Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4

Then diagonal OM is not twice the length of diagonal SQ

5 0
2 years ago
Read 2 more answers
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