Work done on cart
:
W
=
6000
J
Kinetic energy of cart
:
E
K
=
6000
J
Explanation:
Work done
W
is defined as the product of force
F
and distance
s
:
⇒
W
=
F
⋅
s
Let's substitute the values of
F
and
s
into the equation:
⇒
W
=
300
N
⋅
20
m
⇒
W
=
300
kg
⋅
m s
−
2
⋅
20
m
⇒
W
=
300
⋅
20
kg
⋅
m
2
s
−
2
⇒
W
=
6000
kg
⋅
m
2
s
−
2
∴
W
=
6000
J
The gain in kinetic energy
E
K
is the same amount as the work done moving the cart:
∴
E
K
=
6000
Hope you could understand.
If you have any query, feel free to ask.
Answer:
2) y = x - 4
y = -x + 2
=> x - 4 = -x + 2
=> 2x = -6
=> x = -3
=> y = -3 - 4 = -7
3) y = 3x + 1
y = 5x - 3
=> 3x + 1 = 5x - 3
=> 2x = 4
=> x = 2
=> y = 3(2) + 1 = 7
4) 2x + y = 8 => y = -2x + 8
y = x - 7
=> -2x + 8 = x - 7
=> 3x = 15
=> x = 5
=> y = 5 - 7 = -2
The x axis of the point is being translated three units to the left (going from 6 to 3)
The y axis of the point is being translated 2 units down (going from 4 to 2)
The value of the expression would decrease because if you add more to the smallest number in the subtraction problem the value or the answer decreases
