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Allisa [31]
3 years ago
8

Sean is comparing dog food prices.At pet foods store,the total weight of a bag of dog food varies directly with the number of ba

gs.Each bag costs $46.04.another store Healthy Pets sells dog food in 50 lb bags. Each bag costs $88.45. How much would Sean save by buying a 150 lb of dog food from Pet Foods instead of Healthy pets?
Mathematics
1 answer:
12345 [234]3 years ago
7 0

Answer:

Step-by-step explained :

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Product of -28 and sum of 3
ale4655 [162]
-4 and 7 would be the answer
3 0
3 years ago
Read 2 more answers
What is the value of x in the equation 2x + 3y = 36, when y = 6?
amm1812

Answer:

9

Step-by-step explanation:

When plugging 6 in for y, you get  

2x + 3(6) = 36

You have to multiply 3 and 6, getting

2x + 18 = 36.

Now, you subtract 18 from both sides to isolate the x variable, getting

2x = 18

Now, you divide 2 from both sides because we want x standing by itself, getting

x = 9

Therefore, your answer is 9.

Hope this helped

ps accepting brainliest ;)

3 0
2 years ago
Read 2 more answers
A high school principal wishes to estimate how well his students are doing in math. Using 40 randomly chosen tests, he finds tha
ollegr [7]

Answer:

99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Step-by-step explanation:

We are given that a high school principal wishes to estimate how well his students are doing in math.

Using 40 randomly chosen tests, he finds that 77% of them received a passing grade.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

                          P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of students received a passing grade = 77%

           n = sample of tests = 40

           p = population proportion

<em>Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5%

                                           level of significance are -2.5758 & 2.5758}  

P(-2.5758 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

P( \hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

<u>99% confidence interval for p</u> = [\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

 = [ 0.77-2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } } , 0.77+2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } } ]

 = [0.5986 , 0.9414]

Therefore, 99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Lower bound of interval = 0.5986

Upper bound of interval = 0.9414

6 0
2 years ago
Can someone help me plzzzzzzzzz I’m failing math rn
zysi [14]

Answer:

number 1 is b

Step-by-step explanation:

4 0
2 years ago
What is 32 rounded to the nearest hundred
Anni [7]
It would be 100 since it it the closest 100


7 0
3 years ago
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