Pennsylvania has a land area of 44,816 spaure miles

How do i solve this step by step? <br><br> 3( q – 3 ) = 6

mote1985 [20]

Answer:

3q-9=6

3q=9+6

3q=15

q=5

7 0

2 years ago

Nathan went shopping for a new camera because of a sale. The store was offering a 40% discount. If the price on the tag was $35,

tia_tia [17]

Answer:

The price after the discount but before the tax is $21

Step-by-step explanation:

Here, we are told there is a price off of 40% on an item that costs $35.

What we want to calculate is the value of what the price would be before the tax

We proceed by finding 40% of $35

Mathematically, that would be;

40/100 * 35 = $14

The price of the item before the tax is thus;

35-14 = $21

4 0

2 years ago

The mathematical 9 € t means

Kamila [148]

It means <span>9 is not an element of T. hope it helped</span>

8 0

2 years ago

4 thousands + 21 tens

mafiozo [28]

4 x 1 thousand (1000) = 4000

21 x 1 ten (10) = 210

4000
+ 210
---------
4210

=4210 (four thousand-two hundred and ten

7 0

2 years ago

Read 2 more answers

Based on an indication that mean daily car rental rates may be higher for Boston than for Dallas, a survey of eight car rental c

Elina [12.6K]

Answer:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

Step-by-step explanation:

Data given

$n_1 =8$ represent the sample size for group Boston

$n_2 =9$ represent the sample size for group Dallas

$\bar X_1 =47$ represent the sample mean for the group Boston

$\bar X_2 =44$ represent the sample mean for the group Dallas

$s_1=3$ represent the sample standard deviation for group Boston

$s_2=3$ represent the sample standard deviation for group Dallas

We can assume that we have independent samples from two normal distributions with equal variances and that is:

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

Let the subindex 1 for Boston and 2 for Dallas we want to check the following hypothesis:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t student distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

Replacing we got:

$\S^2_p =\frac{(8-1)(3)^2 +(9 -1)(3)^2}{8 +9 -2}=9$

And the deviation would be just the square root of the variance:

$S_p=3$

The statitsic would be:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

5 0

2 years ago