Any measurement that includes both magnitude and direction is called a

Plzzzzzzzzzzzzzzzzzzzzzzzz help

AfilCa [17]

Gases, bc its expand the most upon heating because the intermolecular space is more than in solids or liquids.

intermolecular space = the space between each particles

8 0

3 years ago

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For a hydrogen-like atom, classify these electron transitions by whether they result in the absorption or emission of light.

Nataly_w [17]

Explanation:

When an electron absorbs the light it jumps from its lower energy state towards the higher energy state. This known as absorption.

When an electron come backs from higher energy to lower energy level energy is released emitted out in the form of light. This is known as emission.

1) n = 3 to n = 5 ,This transition will be absorption.

2) n = 1 to n = 3 ,This transition will be absorption

3) n = 3 to n = 2 ,This transition will be emission.

4) n = 2 to n = 1 ,This transition will be emission.

7 0

3 years ago

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What are the steps used in the scientific method?

Stella [2.4K]

1) make an observation
2)form a question
3)form a hypothesis
4)conduct an experiment
5) analyse the data and draw a conclusion

7 0

3 years ago

If you have 6.0-g of lithium and you add it to excess manganese (IV) oxide, how many grams of the product Li2O do you form theor

Kazeer [188]

Taking into account the reaction stoichiometry, 12.857 grams of Li₂O are formed when 6 grams of Li reacts.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

4 Li + MnO₂ → 2 Li₂O + Mn

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Li: 4 moles
MnO₂: 1 mole
Li₂O: 2 moles
Mn: 1 mole

The molar mass of the compounds is:

Li: 7 g/mole
MnO₂: 87 g/mole
Li₂O: 30 g/mole
Mn: 55 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Li: 4 moles ×7 g/mole= 28 grams
MnO₂: 1 mole ×87 g/mole= 87 grams
Li₂O: 2 moles ×30 g/mole= 60 grams
Mn: 1 mole ×55 g/mole= 55 grams

<h3>Mass of Li₂O formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 28 grams of Li form 60 grams of Li₂O, 6 grams of Li form how much mass of Li₂O?

$mass of Li_{2} O=\frac{6 grams of Lix60 grams of Li_{2} O}{28 grams of Li}$