The question is incomplete, the complete question is shown in the image attached to this answer.
Answer:
a) Br^-
b) FeCl3
c) slower
d) see the first attached image
Explanation:
Aromatic compounds undergo electrophilic substitution sections in the presence of the appropriate electrophile.
In the reaction above, the Br^- nucleophile attacks the Lewis acid FeCl3. Recall that the nitro group is meta directing hence the incoming Br^+ electrophile is directed towards the meta position as shown in the image attached.
Note that the nitro group deactivates the ring towards electrophilic substitution hence the reaction is slower with nitrobenzene than with unsubstituted benzene.
Answer:
1) Add more sulfate ions.
2) 1 M K₂SO₄.
Explanation:
<em>1) Which of the following actions would shift this reaction toward solid barium sulfate?</em>
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- Le Châtelier's principle states that if a stress is applied to a system at equilibrium, the system will shift to relieve that stress and attain the equilibrium again.
Add more sulfate ions will increase the concentration of the products side, so the reaction will be shifted towards the reactants side to relieve the stress and attain the equilibrium again.
<em>So, the right choice is: Add more sulfate ions.</em>
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<em>2) In which of the following would barium sulfate be least soluble? </em>
The answer is 1 M K₂SO₄, it has a common ion effect of SO₄⁻ ions that increase the concentration of the products side, so the reaction will be shifted towards the reactants side to relieve the stress and attain the equilibrium again.
<em>So, the solubility will decrease.</em>
Ne because it it just a regular element (neon)
<span> when the cations of one reactant and the anions of a second reactant found in aqueous solutions combine to </span>form<span> an insoluble ionic solid that we call a </span>precipitate<span>.</span>
