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2 years ago

Soils that allow water to pass through them faster are more _______.

Chemistry

2 answers:

Kruka [31]2 years ago

5 0

Answer: C. permeable

Explanation:

Permeability is a measure of how easily water flows through soil. A soil that is made up of large, jagged rocks is likely to be more permeable than a soil that is made up of compact clay. One way to test a soil's permeability is to pour water through it. More permeable soil will allow water to pass through it rapidly, while less permeable soil will block more of the water.

siniylev [52]2 years ago

4 0

I would say C. Permable

Google def.(of a material or membrane) allowing liquids or gases to pass through it.
"a frog's skin is permeable to water

Porous- (of a rock or other material) having minute spaces or holes through which liquid or air may pass

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A large plate is fabricated from a steel alloy that has a plane strain fracture toughness of 89 MPa (81.00 ksi). If the plate is

likoan [24]

Explanation:

The given data is as follows.

$K_{k}$ = 89 MPa, $\sigma$ = 336 MPa

Y = 0.92

Now, we will calculate the length of critical interior flaw as follows.

$a_{c} = \frac{1}{\pi}(\frac{K_{k}}{\sigma Y})^{2}$

= $\frac{1}{\pi}(\frac{89}{336 \times 0.92})^{2}$

= $\frac{656.38}{3.14}$

= 209.04 mm

Thus, we can conclude that minimum length of a surface crack that will lead to fracture is 209.04 mm.

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3 years ago

Which pair of elements can form an ionic compound? A) Two atoms of hydrogen B) One atom of sodium and one atom of fluorine C) On

polet [3.4K]

The answer would be B. One atom of sodium and one atom of fluorine

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2 years ago

Read 2 more answers

A 25.00 mL sample of 0.320 M KOH is titrated with 0.750 M HBr at 25 °C.

Fudgin [204]

Answer:

a. pH = 13.50

b. pH = 13.15

Explanation:

Hello!

In this case, since the undergoing chemical reaction between KOH and HBr is:

$HBr+KOH\rightarrow KBr+H_2O$

As they are both strong. In such a way, since the initial analyte is the 25.00 mL solution of 0.320-M KOH, we first compute the pOH it has, considering that all the KOH is ionized in potassium and hydroxide ions:

$pOH=-log([OH^-])=-log(0.320)=0.50$

Thus, the pH is:

$pH+pOH=14\\pH=14-pOH=14-0.50\\pH=13.50$

Which is the same answer for a and b as they ask the same.

Moreover, once 5.00 mL of the HBr is added, we need to compute the reacting moles of each substance:

$n_{KOH}=0.02500mL*0.320mol/L=0.00800mol\\\\n_{HBr}=0.005L*0.750mol/L=0.00375mol$

It means that since there are more moles of KOH, we need to compute the remaining moles after those 0.00375 moles of acid consume 0.00375 moles of base because they are in a 1:1 mole ratio:

$n_{KOH}^{remaining}=0.00425mol$

Next, we compute the resulting concentration of hydroxide ions (equal to the concentration of KOH) in the final solution of 30.00 mL (25.00 mL + 5.00 mL):

$[OH^-]=[KOH]=\frac{0.00425mol}{0.03000L}=0.142M$