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4 years ago

Is 289 prime? I need this asap (provide factor tree)

1 answer:

6 0

Answer: 289 is a semi-prime number that is created by doing 17 times 17. 17 is a prime number though. hope this helps.

Step-by-step explanation:

289

17 17

You might be interested in

The digram shows a triangle

Anna71 [15]

Answer:

Step-by-step explanation:

Area of triangle = 1/2 (base × height)

1/2(12*5)=

1/2*60=

30 cm²

3 0

1 year ago

Find two different planes whose intersection is theline:x = 6 + 3ty = -8 - 3tz = -1 - tWrite equations for each plane in the for

alina1380 [7]

Answer:

$x+y=-2$ and $3z-y=5$ are two such planes.

Step-by-step explanation:

To find the two planes whose intersection is the line

$x=6+3t\\ y=-8-3t\\ z=-1-t$

You can say that <em>t</em> is equal to this expression

$t=\frac{x-6}{3} =\frac{y+8}{-3}=-z-1$

Next,

$\frac{x-6}{3} =\frac{y+8}{-3}\\ \frac{y+8}{-3}=-z-1$

Then,

$x+y=-2$ and $3z-y=5$ are two such planes.

You can see in the image attached that the intersection of this planes is the line

$x=6+3t\\ y=-8-3t\\ z=-1-t$

7 0

4 years ago

Fold the paper in half two times open the paper.

Andrej [43]

Yes 2/4 is 1/2 because if you have a pie and you cut it in four pieces then you eat to you only got two pieces left so there you only have half a pie left.

4 0

3 years ago

Volume = LWH<br> L= 2w = 3H = 6.5<br> V= 2x3x6.5<br> V= ?

lions [1.4K]

Answer:

Step-by-step explanation:

2*3*6.5=6*6.5=39

3 0

3 years ago

Read 2 more answers

Find the area of the parallelogram that has adjacent sides Bold u equals Bold i minus 2 Bold j plus 2 Bold kand Bold v equals 3

Mice21 [21]

Answer:

The area of the parallelogram is $A=\sqrt{26}$ .

Step-by-step explanation:

Let's rewrite these two vectors:

$u=i-2j+2k$

$v=0i+3j-k$

Let's recall that the area of the parallelogram is the magnitude of the cross product between these vectors.

We can use the Determinant method to find it.

$u \times v=\left[\begin{array}{ccc}i&j&k\\1&-2&2\\0&3&-1\end{array}\right] = i((-2)*(-1)-2*3)-j(1*(-1)-2*0)+k(1*3-(-2)*0)=i(2-6)-j(-1)+k(3)=-4i+j+3k$

Now, the magnitude is the square root of each component squared. It will be:

$|u \times v|=\sqrt{(-4)^{2}+(1)^{2}+(3)^{2}}=\sqrt{16+1+9}=\sqrt{26}$

Therefore the $A=\sqrt{26}$ .

I hope it helps you!

8 0

3 years ago