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frez [133]
3 years ago
8

Find two different planes whose intersection is theline:x = 6 + 3ty = -8 - 3tz = -1 - tWrite equations for each plane in the for

m Ax + By + C = D.

Mathematics
1 answer:
alina1380 [7]3 years ago
7 0

Answer:

x+y=-2 and 3z-y=5 are two such planes.

Step-by-step explanation:

To find the two planes whose intersection is the line

x=6+3t\\ y=-8-3t\\ z=-1-t

You can say that <em>t</em> is equal to this expression

t=\frac{x-6}{3} =\frac{y+8}{-3}=-z-1

Next,

\frac{x-6}{3} =\frac{y+8}{-3}\\ \frac{y+8}{-3}=-z-1

Then,

x+y=-2 and 3z-y=5 are two such planes.

You can see in the image attached that the intersection of this planes is the line

x=6+3t\\ y=-8-3t\\ z=-1-t

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scoundrel [369]

17) x-8=11

18) 9-x=5

19) x+6=7

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Step-by-step explanation:

17) The difference between a number and 8 is 11

Let number = x

then the equation will be:

x-8=11

Solving:

x-8=11

x=11+8\\x=19

18) Nine less than a number is five.

Let number = x

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19) Seven is equal to a number plus 6

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x+6=7

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Let number = x

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x+(-4)=-18

solving:

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Keywords: Algebraic Expressions

Learn more about Algebraic Expressions at:

  • brainly.com/question/1617787
  • brainly.com/question/1600376
  • brainly.com/question/9720317

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