Answer:
Option C. 13.5 atm
Explanation:
From the question given above, the following data were obtained:
Pressure of Neon (Pₙₑ) = 4.1 atm
Pressure of Argon (Pₐᵣ) = 3.2 atm
Pressure of nitrogen (Pₙ₂) = 6.2 atm
Total pressure (Pₜ) =?
The total pressure in the container can be obtained by adding the pressure of the individual gases. This is illustrated below:
Pₜ = Pₙₑ + Pₐᵣ + Pₙ₂
Pₜ = 4.1 + 3.2 + 6.2
Pₜ = 13.5 atm
Therefore, the total pressure in the container is 13.5 atm
1.39 g HCl
Explanation:
The balanced chemical equation for this reaction is given by
Zn(<em>s</em>) + 2HCl(<em>aq</em>) ---> ZnCl2(<em>aq</em>) + H2(<em>g</em>)
Convert the # of grams of Zn to moles:
1.25 g Zn × (1 mol Zn/65.38 g Zn) = 0.0191 mol Zn
Use the molar ratio to find the # of moles of HCl needed to react completely with the given amount of Zn:
0.0191 mol Zn × (2 mol HCl/1 mol Zn) = 0.0382 mol HCl
Convert this amount to grams:
0.0382 mol HCl × (36.458 g HCl/1 mol HCl) = 1.39 g HCl
Answer:
1)NH4ClO4: acidic
2)NH4CN: basic
3)LiF: basic
4)KCN: basic
5)LiNO3: neutral
6)NH4Br: acidic
7)SrBr2: neutral
Explanation:
Salt is an ionic compound formed by the neutralization reaction between an acid and a base.The cation of base and anion from an acid combines to form a salt while H+ from acid and OH- from base forms water.
1)NH4Cl4: is an acidic salt formed from neutralization reaction between strong acid and a weak base.
2)NH4CN: is a basic salt formed from neutralization reaction between weak acid and weak base.
3)LiF: basic salt formed from neutralization reaction between strong acid and strong base.
4)KCN: basic salt formed from neutralization reaction between weak acid and strong base.
5)LiNO3: neutral salt formed from neutralization reaction between strong acid and strong base.
6)NH4Br: acidic salt formed from neutralization reaction between strong acid and weak base.
7)SrBr2: neutral acid formed from neutralization reaction between
strong acid and strong base.
The solution would be like this for this specific problem:
<span><span>Given:
</span>moles of Fe = 31.0 g</span>
So first, we get the molar mass of Fe2O3:
<span>The molar mass of Fe2O3 = 2 x Fe (2 x 55.85) + 3 x O (3 x
16.00) = 159.7 g/mole. <span>
27.4.0 g Fe2O3 x (1 mole Fe2O3 / 159.7 g Fe2O3) = 0.172moles of
Fe2O3
In the formula Fe2O3, there are 2 Fe. So, 1 mole of the
compound Fe2O3 is composed of 2 moles of Fe.
<span>0.172 moles of Fe2O3 x (2 mole Fe / 1 mole Fe2O3) = 0.344
moles of Fe
Therefore, there are 0.344 moles </span></span><span>of fe that are present in 27.4 g of the
compound.</span></span>