Answer:
%Sgr = 1% (1 sig.fig.)
Explanation:
mass water = 350ml x 0.975g/ml = 341.25g
mass sugar added = 4g
solution mass = 341.25g + 4g = 345.25g
%sugar = (4g/345.25g)·100% = 1.1586% ≅ 1% (1 sig.fig)
It provides a way to test a hypothesis
Answer:
134K
Explanation:
Using the ideal gas law equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (Litres)
n = number of moles (mol)
R = gas constant (0.0821 Latm/Kmol)
T = temperature (K)
Based on the information provided, n = 1.4moles, P = 3.25atm, V = 4.738L, T = ?
3.25 × 4.738 = 1.4 × 0.0821 × T
15.3985 = 0.11494T
T = 15.3985/0.11494
T = 133.969
Approximately;
T = 134K
Will you have to show me what you're talking
