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BigorU [14]
2 years ago
15

How to remove acetone from a school chromebook

Chemistry
2 answers:
ycow [4]2 years ago
8 0
Answer:

Blot the liquid with a dry, white absorbent cloth. Gently scrape up semi-solids with a rounded spoon. Break up solids and use something to remove them

kkurt [141]2 years ago
7 0

Answer:

Apply some dishwashing solution with a white washcloth to the acetone residue and for a few minutes, work in gently from the edges of the spill to the center. Dont rub. Continue until the spill is completely removed.

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An atom with 4 protons, 5 neutrons, and 4 electrons has an atomic mass of _____ amu. (Enter a whole number.)
STatiana [176]
I believe it would be the sum of protons & neutrons which equals 9 amu....
7 0
2 years ago
Read 2 more answers
A hydrocarbon that contains only single bonds between the carbon atoms is called a(n):
lukranit [14]
B - alkane ..... :) .......
3 0
3 years ago
Read 2 more answers
To what volume (in mL) would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN?
CaHeK987 [17]

Answer:

To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN

Explanation:

Dilution is the reduction of the concentration of a chemical in a solution and consists simply of adding more solvent.

In a dilution the amount of solute does not vary. But as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

In a solution it is fulfilled:

Ci* Vi = Cf* Vf

where:

  • Ci: initial concentration
  • Vi: initial volume
  • Cf: final concentration
  • Vf: final volume

In this case:

  • Ci= 1.40 M
  • Vi= 20 mL
  • Cf= 0.088 M
  • Vf= ?

Replacing:

1.40 M* 20 mL= 0.088 M* Vf

Solving:

Vf=\frac{1.40 M* 20 mL}{0.088 M}

Vf= 318.18 mL

<u><em>To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN</em></u>

<u><em></em></u>

7 0
3 years ago
The mass of a proton is 1.00728 amu andthat of a neutron is 1.00867 amu. What is the binding energy pernucleon (in J) of a Co nu
andreyandreev [35.5K]

Answer:

The binding energy per nucleon = 1.368*10^-12  (option D)

Explanation:

<u>Step 1:</u> Data given

The mass of a proton is 1.00728 amu

The mass of a neutron is 1.00867 amu

The mass of a cobalt-60 nucleus is59.9338 amu

Step 2: Calculate binding energy

The mass defect = the difference between the mass of a nucleus and the total mass of its constituent particles.

Cobalt60 has 27 protons and 33 neutrons.

The mass of 27 protons = 27*1.00728 u = 27.19656 u

The mass of 33 neutrons = 33*1.00867 u = 33.28611 u

Total mass of protons + neutrons = 27.19656 u + 33.28611 u = 60.48267 u

Mass of a cobalt60 nucleus = 59.9338 amu

Mass defect = Δm = 0.54887 u

ΔE =c²*Δm

ΔE = (3.00 *10^8 m/s)² *(0.54887 amu))*(1.00 g/ 6.02 *10^23 amu)*(1kg/1000g)

Step 3: Calculate binding energy per nucleon

ΔE = 8.21 * 10^-11 J

8.21* 10^-11 J / 59.9338 = 1.368 *10^-12

The binding energy per nucleon = 1.368*10^-12  (option D)

3 0
3 years ago
CN- is a Bronsted - Lowry base. What will this substance form when it accepts a proton?
sergejj [24]
It will form HCN Hydrogen Cyanide.
8 0
2 years ago
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