The number of cookies packs needed if the treasurer buys 1 package of brownies bites is 5 packs
<h3>Equation</h3>
- Total attendance = 75 people
- Cookies in each pack = 12
- Brownies in each pack = 15
- Number of cookies pack = c
- Number of brownies pack = b
15b + 12c = 75
If 1 package of brownies is bought
15b + 12c = 75
15(1) + 12c = 75
15 + 12c = 75
12c = 75 - 15
12c = 60
c = 60/12
c = 5 packs
- It is a reasonable value in this context
If 9 packages of brownies are bought
15b + 12c = 75
15(9) + 12c = 75
135 + 12c = 75
12c = 75 - 135
12c = -60
c = -60/12
c = -5 packs
- The value is not reasonable in this context
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Each of the toppings cost 2$
Answer:
yes
Step-by-step explanation:
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Yes
Answer:
1.d. None of these measures (do not exist interpreted as all of these exist)
2.The mean is increased from 346.8 to 361.32
Step-by-step explanation:
After calculations we find that all the measures of central tendency exist for this data. The mean , median and mode can be easily calculated .
The mean is 346.8
The mode is 281
The median is 316
Suppose that the measurement 806 (the largest measurement in the data set) were replaced by 1169. The mean would be affected by the change.
The mean is 361.32
The mode is 281
The median is 316
The mean is increased from 346.8 to 361.32
<h3>
Answer: B. About 93%</h3>
You have the correct answer.
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Explanation:
Focus solely on the "in anime club" row. We do this because of the phrasing "given the student is in the anime club". We know for a fact that whoever is randomly picked, they are in the anime club. So we don't have to worry about other data values in the other rows.
Divide the value 0.13 which is in the "takes Japanese" column over 0.14, which is in the "total" column.
Basically we're computing
where A and B represent the events "takes Japanese" and "in anime club" respectively. The upside down U symbol represents intersection to indicate both events are happening at the same time.
So we end up with 0.13/0.14 = 0.92857142857142 which rounds to 0.93, then that converts to 93% when you move the decimal point over to the right two spots.