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andreev551 [17]
2 years ago
10

Can someone help me on this question?

Mathematics
2 answers:
Alex777 [14]2 years ago
7 0
You just forgot 2,18
OleMash [197]2 years ago
6 0

Answer:

1,36

2,18

4,9

3,12

Step-by-step explanation:

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Select the correct answer.What is 2/5 divided by 4/7 by equal to?A.7/5 B.7/10 C.10/7 D.7/5
qwelly [4]
The answer would be A . 7/5
7 0
3 years ago
Read 2 more answers
If u get paid 12.00 dollar 40 hours how much money will i have at the end of the month
Lelechka [254]
If she works 40 hours getting paid $12 an hour she will get $480
3 0
3 years ago
Help even tho it’s multiple choice make sure you are correct... I beg you lol
kondaur [170]

Answer:

The equation of the line is:

y=(-\frac{1}{2})x+1

Therefore, option a is the correct answer.

Step-by-step explanation:

Given the points

  • (-2, 2)
  • (4, -1)

Finding the slope

\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-2,\:2\right),\:\left(x_2,\:y_2\right)=\left(4,\:-1\right)

m=\frac{-1-2}{4-\left(-2\right)}

m=-\frac{1}{2}

As the point-slope form of the equation of the line is

y-y_1=m\left(x-x_1\right)

where m is the slope

substituting the values m=-\frac{1}{2} and the point (-2, 2)

y-y_1=m\left(x-x_1\right)

y-2=\frac{-1}{2}\left(x-\left(-2\right)\right)

y-2=\frac{-1}{2}\left(x+2\right)

y-2=-\frac{1}{2}\left(x+2\right)       ∵\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

Add 2 to both sides

y-2+2=-\frac{1}{2}\left(x+2\right)+2

y=(-\frac{1}{2})x+1

Hence, the equation of the line is:

y=(-\frac{1}{2})x+1

Therefore, option a is the correct answer.

4 0
3 years ago
Please help me out!! :D
Rudik [331]
T_n = a_1 + d(n - 1)


T_n = 52 + 12(n - 1)

T_n = 52 + 12n - 12

T_n = 40 + 12n

When n = 102,
T_{102} = 40 + 12(102) = 1264

Answer: 1264

7 0
3 years ago
Help me please!!!!!!!
salantis [7]

Answer:

It is increasing from -1 to 1.

It is decreasing from negative infinity to -1, then decreases again from 1 to positive infinity.

6 0
3 years ago
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