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yuradex [85]
3 years ago
8

9 through 13 i need help ASAP

Mathematics
1 answer:
Zarrin [17]3 years ago
8 0
I hope this helps you

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Write a quadratic function in standard form whose graph passes through (-11,0), (1,0), and (-3,64).
densk [106]

Answer: (-2,25)

Step-by-step explanation:

6 0
3 years ago
A. (3,-2)<br> B. (2,3)<br> C. (4,1)<br> D. (-1,4)
lana66690 [7]
The answer is b (2,3)
3 0
2 years ago
Use the function values for f and g shown in the table below to evaluate the following expression.
Vikentia [17]

The function f(g(2)) is an illustration of a composite function

The value of f(g(2)) is 2

<h3>How to determine the value of the function f(g(2))?</h3>

Given:

The table of values for functions f(x) and g(x)

To calculate f(g(2)), we start by calculating g(2)

From the table;

g(2) = 6

So, we have:

f(g(2)) = f(6)

From the table;

f(6) = 2

So, we have:

f(g(2)) = 2

Hence, the value of f(g(2)) is 2

Read more about composite functions at:

brainly.com/question/10687170

5 0
2 years ago
Can help me complete this problem please :c
motikmotik

Answer:

A = \dfrac{7}{2}\pi~cm^2

Step-by-step explanation:

There is a formula for the area of a sector given the radius and the angle measure.

A = \dfrac{n}{360^\circ}\pi r

n = angle measure

r = radius

A = \dfrac{140^\circ}{360^\circ}\pi \times (3~cm)^2

A = \dfrac{14}{36}\pi \times 9~cm^2

A = \dfrac{7}{18}\pi \times 9~cm^2

A = \dfrac{7}{2}\pi~cm^2

3 0
3 years ago
Read 2 more answers
a water balloon is tossed into the air with an upward velocity of 25 ft/s its height h(t) in ft after t seconds is given by the
Montano1993 [528]
When the height is 0 that is when it hits the ground
solve
0=-16t²+25x+3
cant factor so use quadratic formula

for
0=ax²+bx+c
x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}

so for
0=-16t²+25t+3
a=-16
b=25
c=3
so

x=\frac{-25+/-\sqrt{25^2-4(-16)(3)}}{2(-16)}
x=\frac{-25+/-\frac{625+192}}{-32}
x=\frac{-25+/-\frac{817}}{-32}
it has to be a positive time

so it will hit the ground after \frac{25+\sqrt{817}}{32} seconds
4 0
3 years ago
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