Answer:
a = 6yd
Step-by-step explanation:
- =
- = 36
= 6
The complete question is
"Point P is the incenter of triangle ABC, PZ = 7 units, and PA = 12 units.
The radius of the incircle centered at point P is ? units."
The radius of the incircle centered at point P is 7 units.
We are given that point P is the incenter of the triangle, and is the center point of the incircle of the triangle.
<h3>What is incircle?</h3>
The incircle is defined as the largest circle that can be made in a triangle and is tangent to each side of the triangle.
Here, The radius of the circle is going to be a perpendicular line from point P to any side of the triangle.
In the triangle ,
PZ = PY = PX,
Each measure of value is equal to the radius of the circle.
Therefore, we already know that PZ = 7 units making the radius, r = 7 units.
Learn more about incircle;
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Answer:
The answer is 34
Step-by-step explanation:
<h3>
<u>Given</u>;</h3>
- a₁ = 310
- a₂ = 304
- a₃ = 298
- n = 47
<h3>
<u>To </u><u>Find</u>;</h3>
<h3>
<u>Formula</u>;</h3>
Now,
Common Difference (d)
d = a₂ – a₁ = 304 – 310 = -6
d = a₃ – a₂ = 298 – 304 = -6
Here, common difference is same everywhere
So,
aₙ = a + (n – 1) × d
a₄₇ = 310 + (47 – 1) × (-6)
a₄₇ = 310 + 46 × (-6)
a₄₇ = 310 – 276
a₄₇ = 34
Thus, The 47th term of this sequence is 34.