Answer: (8^{12})^3=8^{12\times 3}=8^{36}
Step-by-step explanation:
Given : the expression (8^{12})^3
We have to simplify the given expression and choose the correct from the given options.
Consider the expression (8^{12})^3
Using property of exponents,
\left(a^b\right)^c=a^{b\times c}
We have,
(8^{12})^3=8^{12\times 3}=8^{36}
Answer:
4x-15=y
Step-by-step explanation:
The higher the rise over the run the more steep your slope will be thus 4x is less steep than 8x because it does not rise as much.
The y intercept shifted downward means anything (-10>b) can be plausible for b.
Answer:
option (a) f(x)= 1/x+2
Step-by-step explanation:
(a) f(x) = 1/ x+2
To find the restriction for domain , we set the denominator =0 and solve for x
x+2 =0, so x=-2
When x=-2 then denominator becomes 0 that is undefined.
So, domain is all real numbers except -2
(b) f(x)= 2x
In this function, there is no denominator or square root or log function
so there is no restriction for x, hence domain is all real numbers
(c) f(x) = 2x-2
In this function, there is no denominator or square root or log function
so there is no restriction for x, hence domain is all real numbers
f(x) = 1/ sqrt(x+2)
if we have square root in the denominator then we set the denominator >0 and solve for x. because square root of negative values are undefined
x+2>0, x>-2
Hence domain is all real numbers that are greater than -2
Answer:
The correct option is (b).
Step-by-step explanation:
If X 
N (µ, σ²), then 
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z N (0, 1).
The distribution of these z-variate is known as the standard normal distribution.
The mean and standard deviation of the active minutes of students is:
<em>μ</em> = 60 minutes
<em>σ </em> = 12 minutes
Compute the <em>z</em>-score for the student being active 48 minutes as follows:
Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.
The correct option is (b).
