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loris [4]
3 years ago
11

What is the equation of the line graphed below in slope-intercept form

Mathematics
2 answers:
Greeley [361]3 years ago
7 0
Answer is b because the slope is -1/2 and the y intercept is -2
JulijaS [17]3 years ago
5 0

Answer:D is correct

Step-by-step explanation:D is correct.Because it's a down line,and it's y-intercept is 2

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What does it mean to “solve for a variable”?
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it means to find the undefined number

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we solve for the variable by using the elimination method

Step-by-step explanation:

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Someone please help <br> WILL GIVE BRAINLIEST
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Answer:

y=3x+1

Step-by-step explanation:

I'm very bad at explaining things so im sorry if this doesn't make any sense

the y axis goes up

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to fill in the "y = ____x+_____"

you find a point on the line, see how far up it is from 0,0 and put that in the first blank space, in this case its 3. then you find how much it goes over on the x axis. in this case its 1 over. so you would put 1.

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7 0
2 years ago
James earned a total of $900 last week.This total was $10 less than five times the amount he earned last week. How much money di
Hoochie [10]
Hello!

Let's change it to an equation.

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\framebox{x = 182}
4 0
3 years ago
Suppose a simple random sample of size n is drawn from a large population with mean mu and standard deviation sigma. The samplin
Sidana [21]

Answer:

X \sim N(\mu,\sigma)  

Where \mu the mean and \sigma  the deviation

Since the distribution for X is normal then we can conclude that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = \mu

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,\sigma)  

Where \mu the mean and \sigma  the deviation

Since the distribution for X is normal then we can conclude that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = \mu

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}

6 0
3 years ago
Read 2 more answers
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