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3 years ago

Find the area of a triangle with the given base and height 7ft, 2in

Mathematics

2 answers:

Alekssandra [29.7K]3 years ago

6 0

Answer:

A = 84 inches^2

Step-by-step explanation:

We know that the formula for the area of a triangle is given by

A = 1/2 b*h

Let's substitute what we know

We need the units to be the same

Convert 7 ft to inches

1 ft = 12 inches

Multiply both sides by 7

7 ft = 84 inches

A = 1/2 *84*2

A = 84 inches^2

SpyIntel [72]3 years ago

5 0

Area = base • height • 1/2

7ft = 84 in

84 • 2 = 168

168 • 1/2 (/2) = 84

Area is 84 sq in or 7 sq ft

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Inessa05 [86]

Answer:

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Step-by-step explanation:

For PQ and RS to be parallel then

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x - 65 = - 10 ( add 65 to both sides )

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2 years ago

What is the solution to the following system of equations? 4x + 2y = 18 x − y = 3

Ber [7]

For this case we have the following system of equations:

$4x + 2y = 18\\x-y = 3$

To solve, we clear "x" from the second equation:

$x = 3 + y$

We substitute "x" in the first equation:

$4 (3 + y) + 2y = 18\\12 + 4y + 2y = 18\\12 + 6y = 18$

We clear the value of the variable "y":

$6y = 18-12\\6y = 6\\y = \frac {6} {6}\\y = 1$

We look for the value of the variable "x":

$x = 3 + y\\x = 3 + 1\\x = 4$

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$(x, y) :( 4,1)$

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$(x, y) :( 4,1)$

Option D

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2 years ago

What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S

Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is $y=\frac{1}{3} x+2$

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3

And as the line passing through (-3,1) and is perpendicular to 3x + y = -8, product of slopes of two line will be -1 as lies are perpendicular.

Let required slope = x

$\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}$

So we need to find the equation of a line whose slope is $\frac{1}{3}$ and passing through (-3,1)

Equation of line passing through $(x_1 , y_1)$ and having lope of m is given by

$\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)$

$\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}$

Substituting the values we get,

$\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}$

Hence the required equation of line is found using slope intercept form

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3 years ago