Solve for x. Enter your answer in interval notation using grouping symbols <br> X^2 + 5x

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match the system of equations with their so

allochka39001 [22]

Answer:

Part 1) solution {(-5,8),(3,0)} ----> $y+12=x^{2}+x$ and $x+y=3$

Part 2) No solutions ----> $y-15=x^{2}+4x$ and $x-y=1$

Part 3) solution [(-2,5),(3,-5)] ---> $y+5=x^{2}-3x$ and $2x+y=1$

Part 4) No solutions ---> $y-6=x^{2}-3x$ and $x+2y=2$

Part 5) solution [(2,3),(8,9)] ---> $y-17=x^{2}-9x$ and $-x+y=1$

Part 6) solution [(-2,3),(7,-6)] ---> $y-15=-x^{2}+4x$ and $x+y=1$

Step-by-step explanation:

Part 1) we have

$y+12=x^{2}+x$ ----> equation A

$x+y=3$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-5,8) and (3,0)

see the attached figure N 1

Part 2) we have

$y-15=x^{2}+4x$ ----> equation A

$x-y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs

see the attached figure N 2

Part 3) we have

$y+5=x^{2}-3x$ ----> equation A

$2x+y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,5) and (3,-5)

see the attached figure N 3

Part 4) we have

$y-6=x^{2}-3x$ ----> equation A

$x+2y=2$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs

see the attached figure N 4

Part 5) we have

$y-17=x^{2}-9x$ ----> equation A

$-x+y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (2,3) and (8,9)

see the attached figure N 5

Part 6) we have

$y-15=-x^{2}+4x$ ----> equation A

$x+y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,3) and (7,-6)

see the attached figure N 6

5 0

3 years ago

Find the area of the semi circle with Diameter of 4

daser333 [38]

Answer:

Find the area of the semi circle with Diameter of 4

2π

6.3

Step-by-step explanation:

The area formula for semicircle is (πr^2)/2.

r=2 because radius is half of diameter.

(π(2)^2)/2, 2 squared= 4 and half of it is 2. = 2π

2π would round to the nearest tenths is 6.3.

6 0

2 years ago

Find [4(cos15° + isin15°)]^3 and express it in a + bi form.

arsen [322]

Answer:

see explanation

Step-by-step explanation:

Using De Moivre's theorem

Given

[ 4(cos15° + isin15° ) ]³, then

= 4³ [ cos(3 × 15°) + isin(3 × 15°) ]

= 64 (cos45° + isin45° )

= 64 ( $\frac{\sqrt{2} }{2}$ + $\frac{\sqrt{2} }{2}$ i )

= 64 ( $\frac{\sqrt{2} }{2}$ (1 + i) )

= 32 $\sqrt{2}$ (1 + i)

= 32 $\sqrt{2}$ + 32 $\sqrt{2}$ i

3 0

3 years ago

3. Jen’s parents buy a tablet for her to use in school. Of the $1500 cost, her parents expect her to pay back $1000 one year lat

NNADVOKAT [17]

Answer:

Step-by-step explanation:

Using the formula for calculating simple interest as shown;

Simple Interest = Principal * Rate *Time/100

Principal = Cost of tablet = $1500

Interest after one year = $1500-$1000 = $500

Time = 1year

Substituting this values into the formula;

$500 = 1500*rate*1/100\\Cross\ multiplying\\50,000 = 1500 * rate\\Rate = 50,000/1500\\Rate = 33.3%$

The interest rate that her parents assumed is 33.3%

4 0

2 years ago

1 x) = 5x what is<br> (a)?<br> n<br> 17 (1)=-52<br> ()

Sonbull [250]

Answer:

its 78

Step-by-step explanation:

7 0

2 years ago

Solve for x. Enter your answer in interval notation using grouping symbols X^2 + 5x < 24