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Lorico [155]
2 years ago
6

A pet store employee counts 23 heads and 68 feet on the animals in the store. The store currently only has kittens and parakeets

left in the store. How many of each are there?
Mathematics
1 answer:
Aloiza [94]2 years ago
4 0

Answer:

11 kittens and 12 parakeets

Step-by-step explanation:

each kitten has 4 feet while each parakeet has 2

11 x 4 = 44 (kittens)

12 x 2 = 24 (parakeets)

11 + 12 is 23 which is your 23 heads.

44 + 24 is 68 which would be your feet

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Answer:

5i and -5i

Step-by-step explanation:

Imaginary roots come in pairs, so the third root must be a real number.  Therefore, neither 5i nor -5i can be the third root.

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Answer:

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Noah is buying a pair of jeans and using a coupon for 10%off. The total price is $56.70 which includes $2.70 in sales tax. Noah’
lora16 [44]

Answer:

See below.

Step-by-step explanation:

So, we know that Noah's purchase can be modeled by the equation:

x-0.1x+2.70=56.70

Part 1)

The solution to the equation will be the value of x.

In this case, x will represent the original price of the jeans.

We know that Noah has a coupon for 10% off the <em>original price of the jeans</em>.

So, 0.1x will represent how much of the original price Noah gets a a discount on.

Therefore, (x - 0.1x) represents the total cost of the jeans <em>after</em> the coupon.

So, x is our original price of the jeans.

Part 2)

To verify that 70 is <em>not</em> a solution, we can simply substitute 70 for x and check whether or not the equation is true. So:

(70)-0.1(70)+2.7\stackrel{?}{=}56.70

Multiply:

70-7+2.7\stackrel{?}{=}56.7

Subtract:

63+2.7\stackrel{?}{=}56.7

Add:

65.7\neq56.7

However, we <em>can</em> verify that 60 <em>is</em> the solution by substituting. So, substitute 60 for every x:

(60)-0.1(60)+2.7\stackrel{?}{=}5.7

Multiply:

60-6+2.7\stackrel{?}{=}56.7

Subtract:

54+2.7\stackrel{?}{=}56.7

Add:

56.7\stackrel{\checkmark}{=}56.7

So, 60 is indeed the solution and is the value of x.

So, this means that $60 was the original price of the jeans.

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3 years ago
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What is your question?
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