<u>Solution</u><u>:</u>


- Now, square root and square gets cancel out in the LHS. And in the RHS, apply the identity: (a + b)² = a² + 2ab + b².

- Now, transpose 4x and 4 to LHS.

- Now, do the addition and subtraction.

<u>Answer</u><u>:</u>
<u>x </u><u>=</u><u> </u><u>±</u><u> </u><u>3</u>
Hope you could understand.
If you have any query, feel free to ask.
Hi there.
Y = 2x + 3
Solve for y when x = 3
The first thing we need to do is replace x by the 3 in the equation.
Y = 2(3) + 3
Y = 6 + 3
Y = 9
Thus, your answer is : C
Answer:
a c and d
Step-by-step explanation:
The attached graph represents the location of the pH values 0 and 1
<h3>How to plot the points?</h3>
The given parameters are:
pH value 0 = (1, 0)
pH value 1 = (0.1, 1)
This means that we plot a point at the coordinate (1, 0) and another point at the coordinate (0.1, 1).
See attachment for the graph
Read more about graphs at:
brainly.com/question/4025726
#SPJ1
<u>Complete question</u>
The pH value is 0 at (1, 0) and 1 at (0.1, 1).
Using desmos
A. Locate, plot, and label on your graph where the pH value is 0.1
B. Locate, plot, and label on your graph where the pH value is 1.
Answer:
−
4
cot
(
−
45
)
cos
(
390
)
sin
(
330
)
Step-by-step explanation: