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3 years ago

PLEASE HELLP 25 POINTS

Mathematics

2 answers:

Leya [2.2K]3 years ago

8 0

Answer:

Step-by-step explanation:

You may need to clean things up a bit but suppose that

S(1) = a-1

S(2) = a^2 -1

Since this is a geometric series, the geometric ratio is given by

S(2)/ S(1) = (a^2 -1)/ (a-1)

= (a+1)(a-1)/ (a-1)

= a+1

Conclusion:

S(2) = (a+1) S(1) = (a+1) (a-1)

S(3) = (a+1) S(2) = (a+1) (a+1) (a-1) = (a+1)^ (3-1) (a-1)

S(4) = (a+1) S(3) = (a+1) * (a+1)^2 (a-1) ) = (a+1)^(4-1) (a-1)

in general.....

S(n) = (a+1)^ (n-1) (a-1)

S(6) = (a+1)^ (6-1) (a-1)

= (a-1) (a+1) ^ 5

= a^6 + 4 a^5 + 5 a^4 - 5 a^2 - 4 a - 1

Read more on Brainly.com - brainly.com/question/11964426#readmore

gayaneshka [121]3 years ago

5 0

Hello from MrBillDoesMath!

Answer:

a^6 + 4 a^5 + 5 a^4 - 5 a^2 - 4 a - 1

Discussion:

You may need to clean things up a bit but suppose that

S(1) = a-1

S(2) = a^2 -1

Since this is a geometric series, the geometric ratio is given by

S(2)/ S(1) = (a^2 -1)/ (a-1)

= (a+1)(a-1)/ (a-1)

= a+1

Conclusion:

S(2) = (a+1) S(1) = (a+1) (a-1)

S(3) = (a+1) S(2) = (a+1) (a+1) (a-1) = (a+1)^ (3-1) (a-1)

S(4) = (a+1) S(3) = (a+1) * (a+1)^2 (a-1) ) = (a+1)^(4-1) (a-1)

in general.....

S(n) = (a+1)^ (n-1) (a-1)

S(6) = (a+1)^ (6-1) (a-1)

= (a-1) (a+1) ^ 5

= a^6 + 4 a^5 + 5 a^4 - 5 a^2 - 4 a - 1

Hope I didn't screw something here!

Thank you,

MrB

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