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fredd [130]
3 years ago
14

Jon and Anne had an equal amount of money. Jon spent $10. Anne spent $30. Now Jon has twice as much money as Anne. How much did

they have first?
Mathematics
1 answer:
bulgar [2K]3 years ago
8 0
They would have had $50 at the beginning
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Round 7 3/8 to the nearest whole number?!?
DIA [1.3K]

Answer:

7

Step-by-step explanation:

Everything including 1/2 and above rounds up to the next whole number.

3/8 < 4/8

7 and 3/8 rounds to 7

5 0
3 years ago
a white-tailed deer can sprint at speeds up to 30 miles per hour. American bison can run at speeds up to 3,520 per minute. Which
guajiro [1.7K]
For the answer to the question above,
In 1 minute, bison runs 3520 feet
In 60 minutes, the bison would run
3520*60 feet
211200 feet per hour.
These are equivalent to;
40 miles per hour since 1 mile is equivalent to 5280 feet.
The bison is faster by 10 miles per hour
Then If you convert the bison's speed to mph you get that it can run at speeds up to 40 mph.

I got this by seeing how many feet that they run in one hour so 3520 x 60 is 211200 which divided by 5280 is 40 mph.

I hope my answer helped.
5 0
3 years ago
Read 2 more answers
The locus of points idea allows you to define a circle without giving a numerical value for the radius?
Lunna [17]

<span>The answer would be yes, the locus of points idea allows you to define a circle without giving a numerical value for the radius.

A locus of points</span> is the set of <span>points<span>, and only those </span>points</span>, that satisfies given conditions. The locus of points at a given distance from a given point is a circle whose center is the given point<span> and whose radius is the given distance.</span>

4 0
3 years ago
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F is inversely proportional to d2<br> When F=12, d=3<br> Work out F when d=6
Thepotemich [5.8K]

Step-by-step explanation:

F -------> 1/d²

12 -------> 1/3²

12 ×(3/6)² ----->1/6²

3----->1/6²

Force = 3N if d=6

4 0
2 years ago
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(cot^2x - 1)/(csc^2x) = cos2x​
Alex787 [66]

Answer:

Step-by-step explanation:

The idea here is to get the left side simplified down so it is the same as the right side. Consequently, there are 3 identities for cos(2x):

cos(2x)=cos^2x-sin^2x,

cos(2x)=1-2sin^2x, and

cos(2x)=2cos^2x-1

We begin by rewriting the left side in terms of sin and cos, since all the identities deal with sines and cosines and no cotangents or cosecants.  Rewriting gives you:

\frac{\frac{cos^2x}{sin^2x} -\frac{sin^2x}{sin^2x} }{\frac{1}{sin^2x} }

Notice I also wrote the 1 in terms of sin^2(x).

Now we will put the numerator of the bigger fraction over the common denominator:

\frac{\frac{cos^2x-sin^2x}{sin^2x} }{\frac{1}{sin^2x} }

The rule is bring up the lower fraction and flip it to multiply, so that will give us:

\frac{cos^2x-sin^2x}{sin^2x} *\frac{sin^2x}{1}

And canceling out the sin^2 x leaves us with just

cos^2x-sin^2x which is one of our identities.

5 0
3 years ago
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