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fredd [130]
3 years ago
14

Jon and Anne had an equal amount of money. Jon spent $10. Anne spent $30. Now Jon has twice as much money as Anne. How much did

they have first?
Mathematics
1 answer:
bulgar [2K]3 years ago
8 0
They would have had $50 at the beginning
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Factor this problem ?<br> 125 +27y^3
koban [17]

Answer:

(5 + 3y)(25 - 15y + 9y²)

Step-by-step explanation:

This is a sum of cubes and factors in general as

a³ + b³ = (a + b)(a² - ab + b²), thus

125 + 27y³

= 5³ + (3y)³ with a = 5 and b = 3y

= (5 + 3y)(5² - 5(3y) + (3y)² )

= (5 + 3y)(25 - 15y + 9y²)

6 0
3 years ago
3x^2+48=0, solve the equation
MAXImum [283]

Answer:

16 + x2 = 0     (16)

I THINK

Step-by-step explanation: Simplifying

3x2 + 48 = 0

Reorder the terms:

48 + 3x2 = 0

Solving

48 + 3x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-48' to each side of the equation.

48 + -48 + 3x2 = 0 + -48

Combine like terms: 48 + -48 = 0

0 + 3x2 = 0 + -48

3x2 = 0 + -48

Combine like terms: 0 + -48 = -48

3x2 = -48

Divide each side by '3'.

x2 = -16

Simplifying

x2 = -16

Reorder the terms:

16 + x2 = -16 + 16

Combine like terms: -16 + 16 = 0

16 + x2 = 0

The solution to this equation could not be determined.

8 0
2 years ago
1) 26 = 8 + v 2) 3 + p = 8
aleksklad [387]

Answer:

268+v2)3+p=8     =p=−3v2−796

Step-by-step explanation:

Let's solve for p.

(268+v2)(3)+p=8

Step 1: Add -804 to both sides.

3v2+p+804+−804=8+−804

3v2+p=−796

Step 2: Add -3v^2 to both sides.

3v2+p+−3v2=−796+−3v2

p=−3v2−796

<em><u>Hope this helps.</u></em>

5 0
3 years ago
Pls help I really don’t know what to da
Vika [28.1K]

Answer:

1. True, 2. False, 3. I am blind.

Step-by-step explanation:

For the 3rd one I cannot confirm becaue I am blind.

8 0
3 years ago
How to finsd the set of numbers if the mean, median and mode is given
Bad White [126]

Answer:

a) we have the numbers 0, 2, 3, 5, 5. The mean and the median are both 3

b) we have the numbers 0, 0, 3, 5, 7. The mean and the median are both 3

In both cases the mean and the median are 3, but the mode differs. The mean and the median do not uniquely determine the mode.

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
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