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SashulF [63]
3 years ago
9

(-1,2) and (3,4) what's the midpoint ? Show work please.

Mathematics
1 answer:
babymother [125]3 years ago
7 0
The midpoint formula is:
( \frac{x1 + x2}{2} ,  \frac{y1+y2}{2} )
Insert your coordinates.
(\frac{-1+3}{2},  \frac{2+4}{2}) =  (\frac{2}{2},  \frac{6}{2} )
Simplify.
(1,3)
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Given f (x ) = x^2 + 3x + 2 and g (x ) = x + 1, perform the indicated operations.
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(i) (f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = x² + 4·x + 3

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Step-by-step explanation:

The given functions are;

f(x) = x² + 3·x + 2

g(x) = x + 1

(i) (f - g)(x) = f(x) - g(x)

∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1

(f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = f(x) + g(x)

∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3

(f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = f(x) × g(x)

∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2

(f·g)(x) = x³ + 4·x² + 5·x + 2

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3 years ago
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