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Kobotan [32]
3 years ago
8

What is the value of b in the equation below? 9^-8 x 9^-2 = a^b -10 -6 9 16

Mathematics
2 answers:
Ronch [10]3 years ago
5 0
Your answer is the first option, -10

Laws of Indices states that a^b x a^c = a^(b + c), therefore 9^-8 x 9^-2 = 9^(-8 - 2) = 9^-10
lys-0071 [83]3 years ago
3 0

Answer:

-10

Step-by-step explanation:

9^-8 x 9^-2 = a^b

We know that x^y * x^z = x^(y+z)

9^-8 x 9^-2 = 9^(-8+-2) = 9^(-10)

a= 9  

b = -10

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AB lies on a number line. The coordinate of point A is -6. Given that AB=20, what are two possible coordinates for point B?
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Answer:

<em>-26 or 14</em>

Step-by-step explanation:

Given that

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To find:

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Solution:

We are given that:

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In other words, we can use modulus function to define the distance between A and B:

|Coordinates of B - Coordinates of A| = 20

Let the coordinates of B = x

Kindly refer to the attached image for the given situation.

Point B might be either on the left or on the right side of A.

That means:

|x-(-6)| = 20\\\Rightarrow |x+6|=20

Now, let us have a look at the modulus function:

|y|=\left \{ {-{y}\ if\ y0} \right.

So,

|x+6|=\left \{ {-{(x+6)}\ if\ (x+6)0} \right.

(x+6 ) =20\\\Rightarrow x =14

-(x+6 ) =20\\\Rightarrow x =-26

Therefore, the answer is:

<em>-26 or 14</em>

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