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DerKrebs [107]
3 years ago
14

If g=26.4 and F=35 find h

Mathematics
2 answers:
frutty [35]3 years ago
6 0
Can you tell us the equation please?
Free_Kalibri [48]3 years ago
3 0
I believe its 43.6 too
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mary bought a bag of jelly beans there were 24 green ones which made up 8% of all the jelly beans in the bag howmany jelly beans
dimulka [17.4K]
There were 300 jelly beans in the bag. that includes the green ones.

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2 years ago
Solve the following problems.<br> Find x, y
natta225 [31]

Step-by-step explanation:

by using similarity and enlargement

10/8 = 7+y/7

70=56+8y

8y=14

y= 7/4

10/8 = 5+x/5

50=40+8x

x = 8/10 = 4/5

7 0
2 years ago
Read 2 more answers
Suppose that an individual has a body fat percentage of 13.7% and weighs 164 pounds. How many pounds of her weight is made up of
Vinvika [58]
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3 0
3 years ago
Which equation below does NOT represent a function of X A) x=y^2 B) y=x C) y = |x| D) y=x^2 E) y=1
vlabodo [156]

Answer:

A) x = y^{2}

Step-by-step explanation:

An equation is a function of x when x is the independent variable, that is:

y = f(x) (1)

Where y is the dependent variable.

According to this, x = y^{2} does not represent a function of x, since the independent variable is a function of y, that is, x = f(y). Therefore, the correct answer is A.

5 0
3 years ago
Note: Enter your answer and show all the steps
Brilliant_brown [7]

Answer: 1763

Step-by-step explanation:

Split this shape into three spaces, to where there are two square-like shapes above one rectangular shape. Next you will find the area of all three separate shapes and add them up to get your total area.

23m times 12m = 276,

23m times 12m = 276,

31m - 12m = 19m, (Here, we are taking the amounts we know of our rectangular shape to get the formula L times W used for determining this shape's area. We use the length of one of the squares(12m) subtracted by the length of both the rectangular shape and one of the squares.(31m) What we get is the lone value of L.

69m times 19m = 1311.

Add 276 + 276 + 1211. Answer = 1763.

5 0
3 years ago
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