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3 years ago

9

A circle has a diameter of 41 centimeters. Which equation can be used to find the radius of this circle?

1 answer:

astra-53 [7]3 years ago

3 0

the radius is d/2. r=41/2 r=20.5

Step-by-step explanation:

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What is the area of a 45 degree sector of a circle with a radius of 12 in.

Elodia [21]

given ,

a circle of radius 12 inches

and $\theta$ = 45°

now we know that ,

$\\{Area \: of \: sector = \frac{\theta}{360\degree} \times \pi \: r {}^{2} } \\ \\$

let's now plug in the values of radius and theta as 12 inches and 45° respectively ,

$\\\dashrightarrow \: \frac{45}{360} \times \frac{22}{7} \times 12 \times 12 \\ \\ \dashrightarrow \: \frac{1}{8} \times \frac{22 \times 12 \times 12}{7} \\ \\ \dashrightarrow \: \frac{22 \times 12 \times 12}{56} \\ \\ \dashrightarrow \: \frac{3168}{56} \\ \\ \dashrightarrow \: 56.57 \: inches {}^{2} (approx.)$

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6 0

3 years ago

Find the distance between the points (4, 3) and (0, 3).

Serga [27]

The answer is 5 points

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3 years ago

Read 2 more answers

Area for a kite<br> I don’t know how to find the area pls help

dusya [7]

Answer:

63.966

Step-by-step explanation:

Area of a kite is

$\frac{pq}{2}$

where p and q are the diagonals.

The horinzontial diagonal is 8.

We need to find the vertical diagonal length.

The top triangle diagonal measure is

${4}^{2} + {x}^{2} = {7}^{2}$

$16 + {x}^{2} = 49$

${x}^{2} = 33$

$x = \sqrt{33}$

The bottom triangle diagonal measure is

${4}^{2} + {x}^{2} = {11}^{2}$

$1 6 + {x}^{2} = 121$

${x}^{2} = 105$

$x = \sqrt{105}$

Add the two diagonals.

$\sqrt{105} + \sqrt{33}$

Substitute this in for the formula

$\frac{8 \times ( \sqrt{105} + \sqrt{33} }{2}$

Which simplified gu

Ives us

$63.966$

Round if neededd.

7 0

3 years ago

Given that cos 63°≈ 0.454, enter the sine of a complementary angle.<br> sin

jek_recluse [69]

Answer:

$\cos(63^\circ)$ is the same as $\sin(27^\circ)$ by co-function identities

Step-by-step explanation:

Remember that complementary angles add up to 90°. The angle that i s complementary to 63° is 27°.

Also recall the co-function identities:

sin (90° – x) = cos x
cos (90° – x) = sin x

This means that $\cos(90^\circ-27^\circ)=\sin(27^\circ)\approx0.454$ .

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2 years ago

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tankabanditka [31]

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Step-by-step explanation:

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