We consider the x- and y-coordinates separately. Let the coordinates of G be (x, y). Now considering the x-coordinates:
FG/FH = (x - (-3)) / (-3 - (-3)) = 2/3
x + 3 = (2/3)(6)
x = 1
For the y-coordinates:
FG/FH = (y - 2) / (7 - 2) = 2/3
y - 2 = (2/3)(5)
y = 16/3
Therefore the coordinates of G are (1, 16/3).
Answer:
It's the PURPULE one
Step-by-step explanation:
BTW can u pls help me in my question thanks
Answer:
StartFraction 9 Over 64 EndFraction
Step-by-step explanation:
He must add the square of half the x coefficient. That coefficient is 3/4, so half of it is 3/8 and the square of that is ...
(3/8)^2 = 9/64
Brian mus add 9/64 to boths sides of the equation.
