Answer:
I would say none of the above
Step-by-step explanation:
When you evaluate A & B they both give you negatives So C
Good luck on Khan academy ;)
Answer:
Step-by-step explanation:
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Answer:16
Step-by-step explanation:
Let the number be X
Twice the sum of a number and 5
= 2X+5
Three times the difference of the number and 2
= 3(X - 2)
Since Twice the sum of X and 5 is equal to three times the difference of the X and 2, This means
2(X + 5 )= 3(X - 2)
2X +10 = 3X - 6
3X -2X = 10 + 6 = 16
X = 16
Check
2×(16+5) =3×(16-2)
2×21 = 3×14
42 = 42
Answer:
Let the number be x
The expression above is written as
15x² = 20x
Divide both sides by x
We get
15x²/x = 20x/x
15x = 20
Divide both sides by 15
x = 20/15
x = 4/3
Hope this helps
To answer this question, you need to know that a quarter is worth $0.25 and dimes worth $0.10. In this case, the total number of money that made from quarters and dimes is $2.80
With Q=quarter and D=dime, then the equation should be:
2.80= 0.25 Q + 0.10 D
The condition that needs to be fulfilled in this case is that the quarter should be 8 more than dimes. Then you need to find out the highest possible number of the quarter and lowest possible number of the dimes.
If you divide 2.8 with 0.25 you will found it will be 11.2 but 11 quarter will result with 0.05 value which you cannot remove, so the highest possible of the quarter should be 10.
If the highest possible of the quarter is 10, then the lowest possible of dimes should be:
2.8= 0.25(10) + 0.10D
0.10D= 0.3
D=3
Since 10-3 is 7, then it is not possible for the quarter to be 8 more than the dimes.
