Whoever gets this right gets brainliest note ( ITS 4 FUN ! NOT A GRADE) 2+4x7=?

Help lease this is due tomorrow. help!

____ [38]

Answer:

p(2)= 2(13-P)

p(2)= 2(13-2)

p(2)=2(11)

p(2)= 22

p(3)= 2(13-p)

p(3)= 2(13-3)

p(3)= 2(10)

p(3)= 20

p(4)= 2(13-p)

p(4)= 2(13-4)

p(4)= 2(9)

p(4)= 18

v(4)w(2)= 3v+w

v(4)w(2)= 3(4) + 2

v(4)w(2)= 12+2

v(4)w(2)= 14

v(6)w(3)= 3v+w

v(6)w(3)= 3(6)+3

v(6)w(3)= 18+3

v(6)w(3)= 21

v(8)w(4)= 3v+w

v(8)w(4)= 3(8)+4

v(8)w(4)= 24+4

v(8)w(4)= 28

7 0

3 years ago

An airplane descended 4,000 feet before landing. The integer that represents how many feet the airplane was above the ground bef

NeTakaya

Answer:

Since, an airplane descended 4,000 feet before landing.

Now, we have to determine the integer which represents the number of feet, the airplane was above the ground before its descent.

Before the descent, airplane was at the height of 4,000 feet.

And the distance above the ground is represented by the positive integers and distance below the ground is represented by the negative integers.

Since, 4,000 feet is the distance of airplane above the ground.

So, the airplane was +4,000 feet above the ground before its descent.

8 0

4 years ago

haley bought 3 note books that each cost the same amount and 1 backpackthat cost $36. the item she bought cost a total of $48 be

nydimaria [60]

Answer:

Step-by-step explanation: Each Notebook Cost $4

If haley Bought 1 Backpack That Was $36 Dollars, Subtract The Number 36 From The Total Amount She Paid For Everything. 48-36 = 12.

If She Bough 3 Notebooks, Divide How Much She Paid By How Many Notebooks She Bought.

12 Divided By 3 Is 4

4 Is The Answer

Hope It Helped (:

3 0

4 years ago

Find the dimensions of a rectangle (in m) with area 1,000 m2 whose perimeter is as small as possible. (Enter the dimensions as a

Amanda [17]

The perimeter of the rectangle is the sum of its dimensions

The dimensions that minimize the perimeter are $\mathbf{10\sqrt{10 },10\sqrt{10 }}$

The area is given as:

$\mathbf{A = 1000}$

Let the dimension be x and y.

So, we have:

$\mathbf{A = xy = 1000}$

Make x the subject

$\mathbf{x = \frac{1000}{y}}$

The perimeter is calculated as:

$\mathbf{P = 2(x + y)}$

Substitute $\mathbf{x = \frac{1000}{y}}$

$\mathbf{P = 2(\frac{1000}{y} + y)}$

Expand

$\mathbf{P = \frac{2000}{y} + 2y}$

Differentiate

$\mathbf{P' = -\frac{2000}{y^2} + 2}$

Set to 0

$\mathbf{ -\frac{2000}{y^2} + 2 = 0}$

Rewrite as:

$\mathbf{ -\frac{2000}{y^2} = -2}$

Divide both sides by -1

$\mathbf{\frac{2000}{y^2} = 2}$

Multiply y^2

$\mathbf{2000 = 2y^2}$

Divide by 2

$\mathbf{1000 = y^2}$

Take square roots of both sides

$\mathbf{y = \sqrt{1000 }}$

$\mathbf{y = 10\sqrt{10 }}$

Substitute $\mathbf{y = \sqrt{1000 }}$ in $\mathbf{x = \frac{1000}{y}}$

$\mathbf{x = \frac{1000}{\sqrt{1000}}}$

$\mathbf{x = \sqrt{1000}}$

$\mathbf{x = 10\sqrt{10 }}$

Hence, the dimensions that minimize the perimeter are $\mathbf{10\sqrt{10 },10\sqrt{10 }}$