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kari74 [83]
4 years ago
5

A random sample of 10 subjects have weights with a standard deviation of 11.0482 kg. What is the variance of their​ weights? Be

sure to include the appropriate units with the result.
Mathematics
1 answer:
IrinaVladis [17]4 years ago
7 0

Answer:

122.0627 kg^2.

Step-by-step explanation:

The standard deviation is the square root of the variance so in this case the variance [email protected]

11.0482  ^ 2

= 122.0627 kg^2.

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tom and lisa each had a birthday party at hurricane harbor last weekend . the cost of admission was $137.50 for 13 children and
gregori [183]

Answer:

Per child admission costs $8.5

Per Adult admission costs $13.5

Step-by-step explanation:

Let x be the amount of admission per child and y be the amount of admission per adult

For Tom's party:

13x+2y=137.50      (Equation 1)

For Lisa's Party:

9x+2y=105.50       (Equation 2)

Using Elimination Method:

Add Equation 1 & 2

13x+2y=137.50

9x+2y=105.50  

-    -   = -         (Change of Signs)

---------------------------------

4x+0y=34.00      

x=34/4

x=8.5

Putting the value of x in Equation 2

13(8.5)+2y=137.50

110.5+2y=137.50

2y=137.50-110.50

2y=27

y=27/2

y=13.5

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3 years ago
Pls help in this IXL asap
Ivahew [28]

Answer:

Step-by-step explanation:

Triangle BCD is a right angle triangle.

From the given right angle triangle

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Taking 45 degrees as the reference angle,

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BD represents the opposite side of the right angle triangle.

To determine BC, we would apply trigonometric ratio

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BC = 2√2 × √2/2

BC = 2

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