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2 years ago

Can someone please help me with this it’s a test

Mathematics

1 answer:

posledela2 years ago

8 0

Answer:

on the app store download the app called mathaway enter the thingys and itll give u your answer

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If a pine tree grows 4 inches per year, how long will it take for the tree to reach a height of 13 feet?

attashe74 [19]

Answer:

Should be 39 years.

there is 12 inches in a foot. and if the tree grows 4 inches every year, then in 3 years the tree would be 1 foot. 13 x 3 = 39, thus proving that in 39 years, it will be 13 feet tall. I may be wrong but this sounds correct.

5 0

3 years ago

Read 2 more answers

Find the curl of ~V ~V = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k

ch4aika [34]

Given

$\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k$

the curl of $\vec v$ is

$\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

7 0

2 years ago

What is the result when the number is 72 is decreased by 44%. Round your answer to the nearest tenth?

Sonbull [250]

The answer is 164 I believe

4 0

3 years ago

Coach Jamison wants to celebrate the final win of the school's baseball season with a trip to the local fast food place. The tea

PIT_PIT [208]

So we have 2 variables here: tacos and orders of nachos.

When we translate the paragraphs into equation: $28t + 27n = 114.80 \\ \\ 12t + 3n = 37.20$

Now, in this situation we can make use the elimination method by converting 3n to -27n.

$- 108t - 27n = - 334.8$

Add both equations: $28t + 27n - 108t - 27n = 114.8 - 334.8 \\ \\ - 80t = - 220 \\ \\ t = 2.75$

So we find that one taco costs $2.75.

We can plug this into any of the first two equations to find n: $12 \times 2.75 + 3n = 37.2 \\ \\ 33 + 3n = 37.2 \\ \\ 3n = 4.2 \\ \\ n = 1.4$

So one order of nachos cost $1.40.

4 0

2 years ago

3x + 2y — z + 5w = 20 y = 2z – 3w z= w+1 2w =8

satela [25.4K]

Answer:

this is tricky ngl

5 0

2 years ago