Ask question

Ask question

All categories

3 years ago

8

Ok what is 84% of 311?

2 answers:

kobusy [5.1K]3 years ago

8 0

It would be: 311*84 / 100 = 311 * 0.84 = 261.24
So, your answer is 261.24

erastova [34]3 years ago

8 0

84\100 x 311
84 x 311=26124\100
answer=261.24

You might be interested in

Fifty balls numbered 1 through 50 are mixed up in a barrel. How many balls must you draw from the barrel (without looking) to be

ipn [44]

If you draw only 25 balls, you could draw the 25 odd-numbered balls. However, there will then be no odd-numbered balls left, so when you draw two more you will be guaranteed to get two even-numbered balls. Thus, the minimum is 25+2=27 balls.

8 0

3 years ago

The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s

Norma-Jean [14]

The positions when the particle reverses direction are:

$s(t_1)=55ft\\\\s(t_2)=28ft$

The acceleraton of the paticle when reverses direction is:

$a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}$

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

$s(t)=2t^{3}-21t^{2}+60t+3$

So,

- Derivating to get the velocity function, we have:

$v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60$

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

$v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s$

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

$a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42$

Now, substituting the times to calculate the accelerations, we have:

$a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}$

Now, substitutitng the times to calculate the positions, we have:

$s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft$

Have a nice day!

3 0

3 years ago

How do you solve each system of equations?

stiv31 [10]

Answer:

$x=1,y=3,z=1$

Step-by-step explanation:

$4x-4y+4z=-4$

$4x=-4+4y-4z$

$x=-1+y-z$

Substitute $x=-1+y-z$ into second equation:

$4\left(-1+y-z\right)+y-2z=5$

$-4+4y-4z+y-2z=5$

$5y-6z-4=5$

$y=\frac{6z+9}{5}$

Substitute $x=-1+y-z$ and $y=\frac{6z+9}{5}$ into the third equation:

$\frac{-41z-54}{5}+3=-16$

$-41z-54=-95$

$z=1$

Substitute $z=1$ into $y=\frac{6z+9}{5}$ :

$y=3$

Plug in y and z values into $x=-1+y-z$ :

$x=1$

4 0

3 years ago

Using only addition, how do you add eight 8’s and get the number 1000?

prisoha [69]

Answer: 888+88+8+8+8 = 1,000

Step-by-step explanation: First of all line all your eights' up and then split them

6 0

3 years ago

Can someone pls answer this question what is 12 +z=15

ANTONII [103]

12 + z = 15

12 - 12 + z = 15 - 12

0 + z = 3

z = 3

3 0

3 years ago

Read 2 more answers