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3 years ago

( 2/3 a^2b^2)^2·(−3ab)^4

Mathematics

1 answer:

german3 years ago

5 0

Solving the expression: $(\frac{2}{3}a^2b^2)^2(-3ab)^4$ we get $36a^8b^8$

Step-by-step explanation:

We need to solve the expression: $(\frac{2}{3}a^2b^2)^2(-3ab)^4$

Solving:

Using exponent rule: $(a^b)^c=a^{bc}$ and another rule: $x^a.x^b=x^{a+b}$

$(\frac{2}{3}a^2b^2)^2(-3ab)^4\\=\frac{4}{9}a^4b^4(81a^4b^4)\\=\frac{4}{9}*81a^{4+4}b^{4+4}\\=4*9a^8b^8\\=36a^8b^8$

So, solving the expression: $(\frac{2}{3}a^2b^2)^2(-3ab)^4$ we get $36a^8b^8$

Keywords: Solving Exponents

Learn more about Solving Exponents at:

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