Answer:
HNO₃
Explanation:
Data given
Nitrogen = 9.8 g
Hydrogen = 0.70 g
Oxygen = 33.6 g
Empirical formula = ?
Solution:
Convert the masses to moles
For Nitrogen
Molar mass of N = 14 g/mol
no. of mole = mass in g / molar mass
Put value in above formula
no. of mole = 9.8 g/ 14 g/mol
no. of mole = 0.7
mole of N = 0.7 mol
For Hydrogen
Molar mass of H = 1 g/mol
no. of mole = mass in g / molar mass
Put value in above formula
no. of mole = 0.70 g/ 1 g/mol
no. of mole = 0.7
mole of H = 0.7 mol
For Oxygen
Molar mass of O = 16 g/mol
no. of mole = mass in g / molar mass
Put value in above formula
no. of mole = 33.6 g / 16 g/mol
no. of mole = 2.1
mole of O = 2.1 mol
Now we have values in moles as below
N = 0.7
H = 0.7
O = 2.1
Divide the all values on the smallest values to get whole number ratio
N = 0.7 / 0.7 = 1
H = 0.7 / 0.7 = 1
O = 2.1 / 0.7 = 3
So all have following values
N = 1
H = 1
O = 3
So the empirical formula will be HNO₃ i.e. all three atoms in simplest small ratio.
Answer:
V₂ = 457.49 mL
Explanation:
Given that,
Initial volume, 
Initial temperature, 
Final temperature, 
We need to find the final volume of the gas. The relation between the volume and the temperature of the gas is given by :
Put the respected values,
So, the final volume of the gas is equal to 457.49 mL.
Answer: They have too many protons in the nucleus.
Explanation: Noble gas. The noble gases are the chemical elements in group 18 of the periodic table. They are the most stable due to having the maximum number of valence electrons their outer shell can hold. Therefore, they rarely react with other elements since they are already stable.
Answer:
one mole of oxygen will produce 
moles of water
Explanation:
The balanced chemical reaction is as follows -
2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O
As we can see in this reaction
5 mole of oxygen (on the reactant side) will produce 2 mole of water (on the product side)
Hence, one mole of oxygen will produce 
moles of water
We no longer use atoms of the same elements are identical in size, mass and properties.
