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Answer:
0.9 liters of 4.0 M NaOH solution will react with 1.8 moles of sulfuric acid.
Explanation:

According to reaction, 1 mole of sulfuric acid reacts with 2 moles of sodium hydroxide.
Then 1.8 moles of sulfuric acid will react with:
moles of NaOH.
Molarity of NaOH = 4.0 M
Moles of NaOH= n = 3.6 mol
Volume of NaOH = V


0.9 liters of 4.0 M NaOH solution will react with 1.8 moles of sulfuric acid.
Answer:
A. Nuclear
Explanation:
This is because it could cause severe environmental damage in areas inhabited by the public
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Answer:
2 NaOH + H2SO4 2 H2O + Na2SO4
How many grams of sodium sulfate will be formed if you start with 200.0
grams of sodium hydroxide and you have an excess of sulfuric acid?
355.3 grams of Na2SO4
200.0 g NaOH 1 mol NaOH 1 mol Na2SO4 142.1 g Na2SO4
40.00 g NaOH 2 mol NaOH 1 mol Na2SO4
= 355.3 g
Explanation:
Answer: Option (4) is the correct answer.
Explanation:
It is known that equilibrium constant is represented as follows for any general reaction.

K = ![\frac{[C][D]}{[A][B]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BC%5D%5BD%5D%7D%7B%5BA%5D%5BB%5D%7D)
As equilibrium constant is directly proportional to the concentration of products so more is the value of equilibrium constant more will be the number of products formed.
As a result, more is the time taken by the reaction to reach towards equilibrium. Whereas smaller is the value of equilibrium constant more rapidly it will reach towards the equilibrium.
Thus, we can conclude that cases where K is a very small number will require the LEAST time to arrive at equilibrium.