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Lena [83]
3 years ago
14

I can distunguish between elements, compounds and mixtures.

Chemistry
1 answer:
FinnZ [79.3K]3 years ago
7 0

Answer: The answer is element

Hope this helps  and please brainliest and ty

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Express 2/10 in scientific notation
Novay_Z [31]
The answer would be 2.0 x 10^-1
5 0
3 years ago
A gas is at a pressure of 3.70 atm. What is this pressure in kilopascals?
Yanka [14]
Answer:
                =   374.90 kPa 

Calculation:
                  As we know atm and kiloPascal are related to each other as,

                                         1 atm  =  101.325 kPa
So,
                                    3.70 atm  =   X
Solving for X,
                                     X  = (3.70 atm × 101.325 kPa) ÷ 1 atm

                                     X  =  374.90 kPa 
7 0
3 years ago
I need help with this question please <br> Chemistry
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3 years ago
_____ is fluffy ice crystals, while _____ is water droplets that freeze on the way down to Earth.
Naily [24]

Answer:

snow,sleet is the answer

Explanation:

7 0
3 years ago
Read 2 more answers
What we call "tin cans" are really iron cans coated with a thin layer of tin. The anode is a bar of tin and the cathode is the i
UNO [17]

Answer:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

Explanation:

Although the context is not clear, let's look at the oxidation and reduction processes that will take place in a Fe/Sn system.

The problem states that anode is a bar of thin. Anode is where the process of oxidation takes place. According to the abbreviation 'OILRIG', oxidation is loss, reduction is gain. Since oxidation occurs at anode, this is where loss of electrons takes place. That said, tin loses electrons to become tin cation:

Sn (s)\rightarrow Sn^{2+} (aq) + 2e^-

Similarly, iron is cathode. Cathode is where reduction takes place. Reduction is gain of electrons, this means iron cations gain electrons and produce iron metal:

Fe^{2+} (aq) + 2e^-\rightarrow Fe (s)

The net equation is then:

Sn (s) + Fe^{2+} (aq)\rightarrow Fe (s) + Sn^{2+} (aq)

However, this is not the case, as this is not a spontaneous reaction, as iron metal is more reactive than tin metal, and this is how the coating takes place. This implies that actually anode is iron and cathode is tin:

Actual anode half-equation:

Fe (s)\rightarrow Fe^{2+} (aq) + 2e^-

Actual cathode half-equation:

Sn^{2+} (aq) + 2e^-\rightarrow Sn (s)

Actual net reaction:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

6 0
2 years ago
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