yes. It would be an irrational number if it didn't repeat in a pattern.
hope it helps comment if u have any questions
Answer: (0.881, 0.919)
Step-by-step explanation:
Let p be the population proportion of respondents who say the Internet has been a good thing for them personally.
Confidence interval for population proportion is given by :-
, where z* = Critical value ,
= Sample proportion
n = sample size.
As per given , we have
n= 957
![\hat{p}=0.90](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%3D0.90)
By z-table , Critical value for 95% confidence interval : z*= 1.96
Then, the 95% confidence interval for the proportion of respondents who say the Internet has been a good thing for them personally. will be :
![0.90\pm 1.96\sqrt{\dfrac{0.90(1-0.90)}{957}}](https://tex.z-dn.net/?f=0.90%5Cpm%201.96%5Csqrt%7B%5Cdfrac%7B0.90%281-0.90%29%7D%7B957%7D%7D)
![0.90\pm 1.96\sqrt{0.0000940438871473}](https://tex.z-dn.net/?f=0.90%5Cpm%201.96%5Csqrt%7B0.0000940438871473%7D)
![0.90\pm 1.96(0.00969762275753)](https://tex.z-dn.net/?f=0.90%5Cpm%201.96%280.00969762275753%29)
![\approx0.90\pm 0.019\\\\=(0.90-0.019,\ 0.90+0.019)](https://tex.z-dn.net/?f=%5Capprox0.90%5Cpm%200.019%5C%5C%5C%5C%3D%280.90-0.019%2C%5C%200.90%2B0.019%29)
![(0.881,\ 0.919)](https://tex.z-dn.net/?f=%280.881%2C%5C%200.919%29)
Hence, the required 95% confidence interval for the proportion of respondents who say the Internet has been a good thing for them personally = (0.881, 0.919)
Vertical Asymptotes is x=3
No Horizontal Asymptotes
Oblique Asymptotes is y=5x
I just want points but your answer is Modelo time
Answer:
8
Step-by-step explanation:
1/2 cup goes into 4 cups 8 times