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Rainbow [258]
3 years ago
11

Is b = 15 a solution to the equation 4b - 20 = 40? yes no WICH ONE

Mathematics
2 answers:
Step2247 [10]3 years ago
8 0

Answer:

Yes

Step-by-step explanation:

4 x 15 = 60. 60 - 20 = 40

Leokris [45]3 years ago
8 0

Answer: yes

Here, we want to decide if 15 is a solution for the equation 4b - 20 = 40. We can do this by simply plugging in 15 for <em>b</em>. If the statement holds true when 15 is plugged in for <em>b</em>, then 15 is a solution.

Plugging in 15 for <em>b</em>, we have 4(15) - 20 = 40.

4(15) is equal to 60.

So we have 60 - 20 = 40 or 40 = 40.

Since the statement holds true, yes,

15 is a solution for the equation.

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Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

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The p value would be given by:

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Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

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