(x - 2)(x² + 2x + 4) = 0

Mathematics

1 answer:

Ber [7]3 years ago

4 0

We have to find the value of x from the given equation.

(x - 2)(x² - 2x + 2) = 0 is a quadratic equation, so it will have two values.

Step: Write the equation in simplest form.

(x - 2)(x² - 2x + 1) = 0

Step: Solve the problem by spiltting method.

(x-2)(x² - x -x + 1) = 0
(x - 2)(x²-x - x + 1) = 0
(x - 2) [x(x - 1) -1(x -1)]
(x - 2)[(x-1)(x-1)]

Step: Solve the problem with using algebraic formula.

{x-1](x-1)

Step : We have used a²-b² to solve the problem.

(x-2)(x² - x -x + 1) = 0

(x - 2)(x²-x - x + 1) = 0

(x - 2) [x(x - 1) -1(x -1)]

(x - 2)[(x-1)(x-1)]

Therefore, the possible factorization is (x - 2)[(x-1)(x-1)].

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scZoUnD [109]

I assume by starting value, you mean y-intercept. The y-intercept is 15

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5 0

3 years ago

Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calcul

sesenic [268]

The expression $5 = \sqrt{(x-6^2)+(y - 5)^2}$ can be used to find the coordinate of Point B. Option C is correct.

Given that,
Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B is to be determined.

<h3>What is the equation?</h3>

The equation is the relationship between variables and represented as y = ax +c is an example of a polynomial equation.

Let the coordinates of B be (x, y)
Now the distance between A (6, 5) and B (x, y) is c = 5 units
So, by the distance formula, the distance between two points is given as,

$C = \sqrt{(x_1-x_2)^2 +(y_1-y_2)^2}$