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3 years ago

How do I solve this step by step

Mathematics

1 answer:

Rom4ik [11]3 years ago

6 0

They are both drawn as right angled triangles so if we can constract them then they should obey pythagoras theorem

First traingle:- 8^2 = 64
7^2 + 6^2 = 49 + 36 = 85 so this does not obey the theorem and you cant draw it.

Second traingle: 9^2 = 81 and 5^2 + 7^2 = 25 + 49 = 75 so we cant draw that one either.

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Rewrite the following expression 15+21 using the GCF and the distributive property

avanturin [10]

First, we want to find the GCF of 15 and 21, which is 3. Now we do 15 divided by 3 and 21 divided by 3, which gives us 5 and 7. To rewrite the expression, we take the GCF and put it on the outside of the parenthesis. Inside the parenthesis, we put 5 + 7. So it'll look like this:

3(5 + 7)

3 0

3 years ago

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On a coordinate plane, 2 lines are shown. Line P Q has points (negative 8, 2) and (4, 2). Line M N has points (8, 6) and (8, neg

DaniilM [7]

Answer:

Slope of PQ = 0

Slope of MN = infinity

PQ and MN are perpendicular to each other

Step-by-step explanation:

for any two points (x1, y1), (x2, y2)given in coordinate plane slope is given by

$y1 - y2/x1-x2\\\\For \ line \ PQ\\slope = 2 - 2/-8-4 = 0\\\\For \ line \ MN \\slope = 6 - (-8)/8-8 = 1/0 = infinity\\\\$

For any line if slope is zero it is parallel to X axis and perpendicular to Y axis

For any line if slope is infinity it is parallel to Y axis and perpendicular to X axis

Also we know X and Y are perpendicular to each other.

Since slope of PQ is zero it is parallel to X axis and perpendicular to Y axis

Since slope of MN is infinity it is parallel to Y axis and perpendicular to X axis.

Thus two lines PQ and MN are perpendicular to each other.

4 0

3 years ago

Read 2 more answers

1)Sheyna drive to the lake and back. It took two hours less time to get there than it did to get back. The average speed on the

ipn [44]

Answer:

8 hours

Step-by-step explanation:

Given:

Sheyna drives to the lake with average speed of 60 mph and

$v_1 = 60\ mph$

Sheyna drives back from the lake with average speed of 36 mph

$v_2 = 36\ mph$

It took 2 hours less time to get there than it did to get back.

Let $t_1$ be the time taken to drive to lake.

Let $t_2$ be the time taken to drive back from lake.

$t_2-t_1 = 2$ hrs ..... (1)

To find:

Total time taken = ?

$t_1+t_2 = ?$

Solution:

Let D be the distance to lake.

Formula for time is given as:

$Time =\dfrac{Distance}{Speed }$

$t_1 = \dfrac{D}{60}\ hrs$

$t_2 = \dfrac{D}{36}\ hrs$

Putting in equation (1):

$\dfrac{D}{36}-\dfrac{D}{60} = 2\\\Rightarrow \dfrac{5D-3D}{180} = 2\\\Rightarrow \dfrac{2D}{180} = 2\\\Rightarrow D = 180\ miles$

So,

$t_1 = \dfrac{180}{60}\ hrs = 3 \ hrs$

$t_2 = \dfrac{180}{36}\ hrs = 5\ hrs$

So, the answer is:

$t_1+t_2 = \bold{8\ hrs}$

8 0

3 years ago

Use the numbers listed to make the equation true<br><br> 2,6 and 5<br> __ + __ X_ = 16

olya-2409 [2.1K]

Due to the order of operations the correct answer is 6+2*5=16

3 0

3 years ago

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Sam Long anticipates he will need approximately $227,300 in 14 years to cover his 3-year-old daughter's college bills for a 4-ye

SSSSS [86.1K]

Answer:

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Step-by-step explanation:

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3 years ago