Given that B is the midpoint of AC, and E is the midpoint of AD, prove △ABE and △ACD are similar.
1 answer:
You might be interested in
9514 1404 393
Answer:
38.5°
Step-by-step explanation:
A triangle solver can give an answer easily. The angle is 38.5°.
__
The law of cosines can be written to solve for an unknown angle C opposite side 'c' and flanked by sides 'a' and 'b'.
C = arccos((a² +b² -c²)/(2ab))
Here, we have a=35, b=48, c=30, so the angle is ...
C = arccos((35² +48² -30²)/(2·35·48)) = arccos(2629/3360) ≈ 38.515°
The angle the cable makes with the pole is about 38.5°.
Answer:
63.6
Step-by-step explanation: