Would this work? Hope it helps
A. At the very end
B.one more away from that
C.on the left
We know that
cos A=adjacent side angle A/hypotenuse
adjacent side angle A=24 units
hypotenuse=26 units
cos A=24/26-----> 12/13
cos B=adjacent side angle B/hypotenuse
adjacent side angle B=10 units
hypotenuse=26 units
cos B=10/26------> 5/13
the answers are
cos A=12/13
cos B=5/13
cot A=adjacent side angle A/opposite side angle A
adjacent side angle A=24 units
opposite side angle A=10 units
cot A=24/10------> cot A=12/5
cot B=adjacent side angle B/opposite side angle B
adjacent side angle B=10 units
opposite side angle B=24 units
cot B=10/24------> cot B=5/12
1 Factor completely.
p2+7p+10 = (p + 5)(p + 2)
2 Factor completely.
x2+10x+16 = (x + 4)(x + 6)
3 Factor completely.
x2+7x−18 = (x + 9)(x - 2)
4 Factor completely.
x2−5x−24 = (x - 8)(x + 3)
5 Factor completely.
x2−3x−40 = (x - 8)(x + 5)
The answer is a if it’s not a I’m sorry but I love you
