What is the solution or solutions of 2^x=7
1 answer:
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Answer:
1) For each value of x, a value of y is increased by 5.
x = 0, y = 5
x = 1, y = 10
x = 2, y = 15
x = 3, y = 20
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2) For each two values of x, a value of y is increased by 10.
x = 0, y = -2
x = 2, y = 8
x = 4, y = 18
x = 6, y = 28
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3)
x = 0, y = 1
x = 1, y =
x = 5, y = 3
x = 10, y = 5
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4)
x = 0, y = 2
x = 1, y = 17
x = 2, y = 32
x = 5, y = 77
Step-by-step explanation:
This is as easy as replacing x for the actual value show on the table.
1)
When x = 0, y = ?
When x = 1, y = ?
When x = 2, y = ?
When x = 3, y = ?
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2)
When x = 0, y = ?
When x = 2, y = ?
When x = 4, y = ?
When x = 6, y = ?
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3)
When x = 0, y = ?
When x = 1, y = ?
When x = 5, y = ?
When x = 10, y = ?
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4)
When x = 0, y = ?
When x = 1, y = ?
When x = 2, y = ?
When x = 5, y = ?