Percentage error = ((12.7/11.5)-100%)x 100% = 10.4% (3 s.f.)
Since the measured yield exceeds the theoretical one, this means the error is in excess. Divide the measured yield by the theoretical yield and subtract 100% to find the difference, then multiply by 100% to find the percentage.
The strong electrolyte KF completely dissociates into K+ and
F- ions when it dissolves in water. When the weak electrolyte HF dissolves in
water, there are a few ions of H+ and F- present, but mostly dissolved HF
molecules. I am hoping that this answer has satisfied your query
and it will be able to help you in your endeavor, and if you would like, feel
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